I don't know man hahahaha
Answer:
C₃H₈₍g₎ + 5O₂₍g₎→ 3CO₂₍g₎ + 4H₂O₍l₎
Explanation:
Propane is an alkane that burns in enough oxygen to produce carbon (iv) Oxide and heat as the only by products. Balancing the equation: The number of atoms of each kind on either side should be equal. Hydrogen on the left has eight atoms same as the right side after balancing, oxygen has 10 while carbon has 3 on each side.
Answer: yes
Explanation: it is always in a conductive state
Missing question:
(a) 1s2 2s2 2p6 3s1
(b) 1s2 2s2 2p6 3s2
(c) 1s2 2s2 2p6 3s2 3p1
(d) 1s2 2s2 2p6 3s2 3p4
(e) 1s2 2s2 2p6 3s2 3p5
Answer is: a) 1s²2s²2p⁶3s¹ (sodium).
Sodium have the largest second ionization energy, because when he lost one electron(first ionization energy), he have stable electron configuration of noble gas neon (1s²2s²2p⁶), so sodium do not need to lost second electron, because he will have unstable electron configuration.
Answer:
- 2K(s) + (1/8) S₈ (s) + (3/2) O₂(g) → K₂SO₃ (s)
Explanation:
The<em> standard enthalpy of formation </em>of a substance is the change in enthalpy that happens when one mole of the substance is formed from the elements in their standard states.
Thus, to calculate the standard state of formation of a compound you must:
- 1. Identify the elements that form the compound
- 2. Identify the standard form of each element
- 3. Set the equation to form one mole of the compound, which may require to use fractional coefficients for some of the elements.
Applying that to our compound K₂SO₃
<u>1. Elements:</u>
- potassium, K;
- sulfur, S; and
- oxygen, O.
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<u>2. Standard forms of the elements:</u>
- potassium: solid, K(s)
- sulfur: solid, octatomic molecules, S₈ (s)
- oxygen: diatomic gas, O₂(g)
<u>3. Reaction:</u>
- K(s) + S₈ (s) + O₂(g) → K₂SO₃ (s)
Balance, keeping one mole of K₂SO₃. You will need to use fractional coefficients for some elements:
- 2K(s) + (1/8) S₈ (s) + (3/2) O₂(g) → K₂SO₃ (s) ← answer
