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2 years ago

PLZ HELP!

Chemistry

1 answer:

kaheart [24]2 years ago

5 0

Answer:

You

Explanation:

When you divide 100 by 15 you get 6.6666666. When you divide 100 by 14 you get 7.14.

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The heat of vaporization of 1–pentanol is 55.5 kJ/mol, and its entropy of vaporization is 148 J/K•mol. What is the approximate b

tensa zangetsu [6.8K]

Answer:

375 K

Explanation:

Using the experssion shown below as:

$\Delta G^0=\Delta H^0_{vap}-T\Delta S^0_{vap}$

At vaporization point, the liquid and the gaseous phase is in the equilibrium.

Thus,

$\Delta G^0=0$

So,

$Delta H^0_{vap}=T\Delta S^0_{vap}$

Given that:

$Delta H^0_{vap}=55.5\ kJ/mol$

Also, 1 kJ = 10³ J

So,

$Delta H^0_{vap}=55500\ J/mol$

$\Delta S^0_{vap}=148\ J/K.mol$

So, temperature is :

$T=\frac{Delta H^0_{vap}}{\Delta S^0_{vap}}$

$T=\frac{55500}{148}$

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3 years ago

Explain why one prevents erosion and the other makes erosion worse.

Studentka2010 [4]

Eroded sediments from further upstream clogged Jakarta’s rivers and canals, causing them to overflow. Similar erosion-related floods have occurred in many other countries, such as Colombia, India, the Philippines and Democratic Republic of the Congo.

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3 years ago

Based on the graph below, which statement

Novay_Z [31]

Answer:

4. Atmospheric pressure decreases as altitude increases.

Explanation:

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2 years ago

An amino acid A, isolated from the acid-catalyzed hydrolysis of a peptide antibiotic, gave a positive ninhydrin test and had a s

Ede4ka [16]

The answer could be 23

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3 years ago

15.1 L N2 at 25 °C and 125 kPa and 44.3 L O2 at 25 °C and 125 kPa were transferred to a tank with a volume of 6.25 L. What is th

Y_Kistochka [10]

Answer:

The total pressure of the mixture in the tank of volume 6.25 litres at 51°C is 1291.85 kPa.

Explanation:

For N2,

Pressure(P₁)=125 kPa

Volume(V₁)=15·1 L

Temperature (T₁)=25°C=25+273 K=298 K

Similarly, for Oxygen,

Pressure(P₂)= 125 kPa

Volume(V₂)= 44.3 L

Temperature(T₂)=25°C= 298 K

Then, for the mixture,

Volumeof the mixture( V)= 6.25 L

Pressure(P)=?

Temperature (T)= 51°C = 51+273 K=324 K

Then, By Combined gas laws,

$\frac{P_{1} V_{1} }{T_{1} } +\frac{P_{2} V_{2} }{T_{2} } =\frac{PV}{T}$

or, $\frac{15.1*125}{298} +\frac{44.3*125}{298} =\frac{P*6.25}{324}$

or, $6.34+18.58=\frac{P*6.25}{324}$

or, $P=\frac{24.92*324}{6.25}$

∴P=1291.85 kPa

So the total pressure of the mixture in the tank of volume 6.25 litres at 51°C is 1291.85 kPa.

3 0

2 years ago