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weeeeeb [17]
3 years ago
7

Which of the following has the lowest boiling point? O HF NaCl O MgCl2 O CH4

Chemistry
2 answers:
dalvyx [7]3 years ago
7 0

Answer:

sheshhhhhhhh naci

Explanation:

melisa1 [442]3 years ago
6 0
The answer is HF he and I DC if
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When 40 grams of ammonium nitrate explode 14 grams of nitrogen and 8 grams of oxygen form. How many grams of water form
DerKrebs [107]

Answer:

18 grams of water

Explanation:

The Balance Chemical Reaction is as follow,

                     2 NH₄NO₃    →    2 N₂  +  O₂  +  4 H₂O

According to Equation,

                     160 g (2 moles) NH₄NO₃ produces  =  72 g (4 moles) of H₂O

So,

                     40 g of NH₄NO₃ will produce  =  X g of H₂O

Solving for X,

                     X =  (40 g × 72 g) ÷ 160 g

                     X  =  18 g of H₂O

<em>Hope This Helps!</em>

4 0
2 years ago
What do ionic compounds form
Snowcat [4.5K]

Answer:

By the result of the formation of positive and negative ions, Ionic compounds are formed.

Explanation:

Electrons are actually transferred from one atom to another to form rare gas electron structures for each ion. The atom which forms a positive ion loses electrons to the atom which gains electrons to form a negative ion. A compound is not stable unless the number of electrons which are lost and gained are equal

3 0
3 years ago
What is the balanced chemical equation when an aqueous solution of calcium hydroxide reacts with liquid water?
Dmitrij [34]

Explanation:

Equation for Calcium Hydroxide Dissolving in Water | Ca(OH)2 + H2O

7 0
2 years ago
How many moles of oxygen are required to produce 4 moles of water?​
kramer

Answer:

6 moles of oxygen

Explanation:We can find from the chemistry equation

C3H7SH(l)+6O2---3CO2(g)+SO2(g)+4H2O(g)

6 moles O2 ~4 moles  H2O

5 0
3 years ago
Read 2 more answers
How many mL of a 1 M NaOH solution are required to neutralize 100 mL of a 2 M H2SO4 solution?
Murljashka [212]

Answer : The volume of 1 M NaOH solution required are, 400 mL

Explanation :

To calculate the volume of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=2M\\V_1=100mL\\n_2=1\\M_2=1M\\V_2=?

Putting values in above equation, we get:

2\times 2M\times 100mL=1\times 1M\times V_2

V_2=400mL

Therefore, the volume of 1 M NaOH solution required are, 400 mL

5 0
3 years ago
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