What are the units for speed A. m/s B. km/s ^ 2 C. m/s^2 D. m^2/s^2

(b) in what way are carbon dioxide and orange juice similar?

ArbitrLikvidat [17]

Answer:

The effects of supercritical CO2 (SC-CO2) on the microbiological, sensory (taste, odour, and colour), nutritional (vitamin C content), and physical (cloud, total acidity, pH, and °Brix) qualities of orange juice were studied. The CO2 treatment was performed in a 1 litre capacity double-walled reactor equipped with a magnetic stirring system. Freshly extracted orange juice was treated with supercritical CO2, pasteurised at 90°C, or left untreated. There were no significant differences in the sensory attributes and physical qualities between the CO2 treated juice and freshly extracted juice. The CO2 treated juice retained 88% of its vitamin C, while the pasteurised juice was notably different from the fresh juice and preserved only 57% of its vitamin C content. After 8 weeks of storage at 4°C, there was no microbial growth in the CO2 treated juice.

6 0

2 years ago

How does heat move between objects that are touching?

Tom [10]

Answer:

Conduction

Explanation:

Conduction is heat transfer between two objects that are touching each other. When two objects touch and one has a higher temperature than the other; heat is transferred to the object with the lower temperature. ... In radiation, heat is transferred from one object to another by electromagnetic waves of energy. Edit : Please mark brainliest if it helped, thanks.

6 0

2 years ago

Given the wavelength of the corresponding emission line, calculate the equivalent radiated energy from n = 4 to n = 2 in both jo

lions [1.4K]

Explanation:

It is given that,

Initial orbit of electrons, $n_i=4$

Final orbit of electrons, $n_f=2$

We need to find energy, wavelength and frequency of the wave.

When atom make transition from one orbit to another, the energy of wave is given by :

$E=-13.6(\dfrac{1}{n_f^2}-\dfrac{1}{n_i^2})$

Putting all the values we get :

$E=-13.6(\dfrac{1}{(4)^2}-\dfrac{1}{(2)^2})\\\\E=2.55\ eV$

We know that : $1\ eV=1.6\times 10^{-19}\ J$

So,

$E=2.55\times 1.6\times 10^{-19}\\\\E=4.08\times 10^{-19}\ J$

Energy of wave in terms of frequency is given by :

$E=hf$

$f=\dfrac{E}{h}\\\\f=\dfrac{4.08\times 10^{-19}}{6.63\times 10^{-34}}\\\\f=6.14\times 10^{14}\ Hz$

Also, $c=f\lambda$

$\lambda$ is wavelength

So,

$\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{6.14\times 10^{14}}\\\\\lambda=4.88\times 10^{-7}\ m\\\\\lambda=488\ nm$

Hence, this is the required solution.

4 0

3 years ago

Fusion reactions constitute the fundamental energy source of stars, including the Sun. Hydrogen “burning” initiates the fusion e

AfilCa [17]

Answer:

C) The most efficient fusion reactors would use heavier forms of hydrogen.

Explanation:

From the information presented to us in the question, the third sentence reveals that heavier forms of hydrogen produces larger amount of energy and most importantly reacts more efficiently when fusion occurs.

In fact, the heavy isotopes of hydrogen—deuterium and tritium—react more efficiently with each other, and, when they do undergo fusion, they yield more energy per reaction than do two hydrogen nuclei.

3 0

3 years ago

What is an element in science

s2008m [1.1K]

An element is a part or aspect of something abstract, especially one that is essential or characteristic. I hope this helps you good luck :)

5 0

3 years ago

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