Answer:

Explanation:
We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.
Mᵣ: 28.01 17.03
N₂ + 3H₂ ⟶ 2NH₃
m/g: 240.0
(a) Moles of NH₃

(b) Moles of N₂

(c) Mass of N₂

Answer:
D. exosphere is the outer layer of the thermosphere
Divide both sides to get 104 and that’s your answer
Answer:Sodium Bicarbonate
Explanation:Crack is manufactured by using Sodium Bicarbonate (NaHCO3) to remove hydrochlorides to create a crystalline form of cocaine that can be smoked.