ABCD is a parallelogram Given
AE=CE, BE=DE <span>The diagonals of a parallelogram are bisect each other
</span>∠AEB=∠CED Vertical angles are congruent
ΔABE is congruent to ΔCDE SAS theorem<span>
</span>
The answer is d= -2an+2s/n^2-n
That answer should be in a fraction form.
27+6(2*2-1)4*2-5
2*2=4
27+6(4-1)4*2-5
4-1=3
27+6(3)4*2-5
6*3=18
27+(18)4*2-5
18*4=72
27+(72)*2-5
72*2=144
27+(144)-5
27+144+171
171-5=166
So the answer is 166.
