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3 years ago

Vitamin C has an empirical formula of C3H4O3 and a molecular mass of 176 amu. What is the molecular formula of vitamin C?

Chemistry

1 answer:

Vinvika [58]3 years ago

3 0

Answer:

(C3H4O3) x 2 = C6H8O6, the molecular formula for Vitamin C.

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What is the formula of the compounds in B<br><br> pls help

grandymaker [24]

Answer:

PCl3

Explanation:

The molecular formular of a compound shows the exact number of atoms of elements present in the compound. In this illustration, there is one atom of P and 3 atoms of Cl.

The formular is given as; PCl3

5 0

3 years ago

Read 2 more answers

Please help.

Anna35 [415]

Answer:

9429.9

Explanation:

periodt

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3 years ago

5.4 When looking down the C{{TOP-HAT-MATH-TOKEN-0}}-C{{TOP-HAT-MATH-TOKEN-1}} bond in 2,3-dimethylbutane, what is the most stabl

AURORKA [14]

Answer:

The most stable conformer would be the anti-conformer when the substituent methyl groups are farthest away from each other.

Explanation:

Isomers are chemical compounds with the same molecular formula but with different molecular structures.

Conformers are a special type of isomers that produce different structures when the substituents of a Carbon-Carbon single bond (C-C) are rotated.

In 2,3 dimethyl butane, the substituent methyl groups are located around the second and third Carbon to Carbon single bond.

To achieve a stable configuration, the methyl group substituents need to be as far apart as possible (that is, in an anti-position) to minimise repulsion.

The closer the methyl groups are to each other, the more they repel each other and the more unstable the conformer becomes.

7 0

3 years ago

Phosphorus pentachloride decomposes according to this equation. PCl5(g) equilibrium reaction arrow PCl3(g) + Cl2(g) An equilibri

melisa1 [442]

Answer:

PCl₅ = 0.03 X 208 = 6.24g

PCl₃ = 0.05 X 137 =6.85 g

Cl₂ = 0.03X71 = 2.13 g

Explanation:

The equilibrium constant will remain the same irrespective of the amount of reactant taken.

Let us calculate the equilibrium constant of the reaction.

Kc= $\frac{[PCl_{3}][Cl_{2}]}{[PCl_{5}]}$

Let us calculate the moles of each present at equilibrium

$moles=\frac{mass}{molarmass}$

molar mass of PCl₅=208

molar mass of PCl₃=137

molar mass of Cl₂=71

moles of PCl₅ = $\frac{mass}{molarmass}=\frac{4.13}{208}=0.02$

moles of PCl₃= $\frac{mass}{molarmass}=\frac{8.87}{137}=0.06$

moles of Cl₂ = $\frac{mass}{molarmass}=\frac{2.90}{71}=0.04$

the volume is 5 L

So concentration will be moles per unit volume

Putting values

Kc = $\frac{\frac{0.06}{5}\frac{0.04}{5}}{\frac{0.02}{5}}=0.024$

Now if the same moles are being transferred in another beaker of volume 2L then there will change in the concentration of each as follow

$PCl_{5}--->PCl_{3}+Cl_{2}$

Initial 0.02 0.06 0.04

Change -x +x +x

Equilibrium 0.02-x 0.06+x 0.04+x

Conc. (0.02-x)/2 (0.06+x)/2 (0.04+x)/2

Putting values

0.024 = $\frac{(0.06+x)(0.04+x)}{(0.02-x)2}$

Solving

$(0.024(2)(0.02-x)=(0.06+x)(0.04+x)$

$0.00096-0.048x=0.0024+x^{2}+0.1x$

$0.148x+x^{2}+0.00144=0$

x = -0.01

so the new moles of

PCl₅ = 0.02 + 0.01 =0.03

PCl₃ = 0.06-0.01 = 0.05

Cl₂ = 0.04-0.01 = 0.03

mass of each will be:

mass= moles X molar mass

PCl₅ = 0.03 X 208 = 6.24g

PCl₃ = 0.05 X 137 =6.85 g

Cl₂ = 0.03X71 = 2.13 g

5 0

3 years ago

How do you determine the number of moles in a sample

AleksandrR [38]

Divide the mass of the compound in grams by the molar mass you just calculated. The answer is the number of moles of that mass of compound.
I hope it helps

3 0

3 years ago