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____ [38]
3 years ago
15

Molar mass of Ag2SO4 Full work Pls

Chemistry
1 answer:
IceJOKER [234]3 years ago
5 0
This would be the molar mass.

You might be interested in
Please help with both
kupik [55]

Answer:

D =Average atomic mass  = 10.801 amu.

5) True

Explanation:

Abundance of B¹⁰= 19.9%

Abundance of B¹¹ = 80.1%

Atomic mass of B¹⁰ = 10 amu

Atomic mass of B¹¹ = 11 amu

Average atomic mass = ?

Solution:

Average atomic mass  = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

Average atomic mass  = (10×19.9)+(11×80.1) /100

Average atomic mass =  199 + 881.1 / 100

Average atomic mass  = 1080.1 / 100

Average atomic mass  = 10.801 amu.

2)A chemical reaction is one in which a new elements is created

True

False

Answer:

In chemical reaction new substances are created.

For example:

Photosynthesis:

It is the process in which in the presence of sun light and chlorophyll by using carbon dioxide and water plants produce the oxygen and glucose.

Carbon dioxide + water + energy →   glucose + oxygen

water is supplied through the roots, carbon dioxide collected through stomata and sun light is capture  by chloroplast.

Chemical equation:

6H₂O + 6CO₂ + energy  →   C₆H₁₂O₆ + 6O₂

it is known from balanced chemical equation that 6 moles of carbon dioxide react with the six moles of water and created one mole of glucose and six mole of oxygen.

8 0
3 years ago
A solution is made by dissolving 0.565 g of potassium nitrate in enough water to make up 250. mL of solution. What is the molari
aalyn [17]
<h3>Molar mass of Potassium Nitrate:-</h3>

\\ \large\sf\longmapsto KNO_3

\\ \large\sf\longmapsto 39u+14u+3(16u)

\\ \large\sf\longmapsto 53u+48u

\\ \large\sf\longmapsto 101u

\\ \large\sf\longmapsto 101g/mol

Now

\boxed{\sf No\:of\:moles=\dfrac{Given\:mass}{Molar\:mass}}

\\ \large\sf\longmapsto No\:of\:moles=\dfrac{0.565}{101}

\\ \large\sf\longmapsto No\:of\:moles=0.005mol

We know

\boxed{\sf Molarity=\dfrac{Moles\:of\:solute}{Vol\:of\:Solution\:in\:L}}

\\ \large\sf\longmapsto Molarity=\dfrac{0.005}{\dfrac{250}{1000}L}

\\ \large\sf\longmapsto Molarity=\dfrac{0.005}{0.250}

\\ \large\sf\longmapsto Molarity=0.02M

8 0
3 years ago
Read 2 more answers
A certain compound contains 4.0 g of calcium and 7.1 g of chlorine. Its relative molecular mass is 111. Find its empirical and m
Phantasy [73]

Given :

A certain compound contains 4.0 g of calcium and 7.1 g of chlorine.

Its relative molecular mass is 111.

To Find :

Its empirical and molecular formulas.

Solution :

Moles of calcium , n_1=\dfrac{4}{40}=0.1\ moles.

Moles of chlorine , n_2=\dfrac{7.1}{35.45}=0.2\ moles .

The ratio calcium and chlorine is 1 : 2 .

So , the empirical formula is CaCl_2 .

Now , molecular mass of CaCl_2 is :

M=40+(2\times 35.45)\\\\M=110.9\ g

So , n=\dfrac{111}{110.9} \approx1

Therefore , the molecular formula is also CaCl_2 .

Hence , this is the required solution .

7 0
3 years ago
so they are asking me to find the empirical formula for a compound that is 7.70% carbon and 92.3% chlorine. Can you show me step
Nikolay [14]

Answer:

Empirical formula is CCl₄

Explanation:

Given data:

Percentage of carbon = 7.70%

Percentage of chlorine = 92.3%

Empirical formula = ?

Solution:

Number of gram atoms of Cl = 92.3 / 35.5 = 2.6

Number of gram atoms of C = 7.70 / 12 = 0.64

Atomic ratio:

            C                      :              Cl            

           0.64/0.64        :             2.6/0.64

            1                      :                4        

C : Cl  = 1 : 4

Empirical formula is CCl₄.

5 0
3 years ago
A 2.0 mL sample of a liquid has a mass of 44.0 g. What is the density of the liquid?
riadik2000 [5.3K]

Answer:

The answer is

<h2>22 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}

From the question

mass of liquid = 44 g

volume = 2 mL

The density of the liquid is

density =  \frac{44}{2}

We have the final answer as

<h3>22 g/mL</h3>

Hope this helps you

8 0
4 years ago
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