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bixtya [17]
3 years ago
12

5.0 kg, with a bullet of mass 0.1 kg. The target was mounted on

Physics
1 answer:
kari74 [83]3 years ago
8 0

Answer:

306 m/s

Explanation:

Law of conservation of momentum

m1v1 + m2v2 = (m1+m2)vf

m1 is the bullet's mass so it is 0.1 kg

v1 is what we're trying to solve

m2 is the target's mass so it is 5.0 kg

v2 is the targets velocity, and since it was stationary, its velocity is zero

vf is the velocity after the target is struck by the bullet, so it is 6.0 m/s

plugging in, we get

(0.1 kg)(v1) + (5.0 kg)(0 m/s) = (0.1 kg + 5.0 kg)(6.0 m/s)

(0.1)(v1) + 0 = 30.6

(0.1)(v1) = 30.6

v1 = 306 m/s

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Look at the diagram of the moon and three different paths that it could take. A planet with a moon in orbit. The moon has arrows
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is 3 and 2

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A 2.2-kg block slides on a horizontal surface with a speed of v=0.80m/s and an
mina [271]

Answer:

μ = 0.33

Equal to 3.2 m/s²

Explanation:

Draw a free body diagram of the block.  There are three forces:

Normal force N pushing up.

Weight force mg pulling down.

Friction force Nμ pushing opposite the direction of motion.

Sum of forces in the y direction.

∑F = ma

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N = mg

Sum of forces in the x direction.

∑F = ma

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μ = a/g

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μ = 0.33

As found earlier, the acceleration is a = gμ.  Since g and μ are constant, a is also constant, so it does not change with velocity.

5 0
3 years ago
If you are driving 80 km/h along a straight road and you look to the side for 2.1 s , how far do you travel during this inattent
ella [17]
Velocity = displacement / time

First, Always make sure that your units for things are the same. In this question, we are given time in seconds and hours. So, we need to make them all use 1 unit.

I will do seconds.

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22.2222…. m/s = displacement / 2.1s

Multiply by 2.1s on both sides

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You travelled 47 meters.
7 0
2 years ago
The​ Eco-Marathon is an annual competition sponsored by Shell​ Oil, in which participants build special vehicles to achieve the
OverLord2011 [107]

Answer:

(1)  V=0.03348 gallons

(2)  L= 576.813 km .

Explanation:

Write the relation between the density and volume for ethanol.

density ( ρ )= m/V

Volume ( V )= m/ρ .......... (1)

Here, V is the volume of ethanol, m is the mass of ethanol, and  is the density of ethanol.

Write the relation between the specific gravity of ethanol and density of water

ρ=γ*ρ(water)  ............. (2)

Here,  is specific gravity of ethanol and  is the density of water.

Determine the volume of ethanol by substituting equation (2) in equation (1)

V=m/γ*ρ(water)

Substitute 100 gm , for m,  for , and 1000 kg/m  for.

V=\frac{100*10^{-3} }{0.789*1000}

V=0.000112674 m^{3

Convert m³ to gallons

V= (0.000112674*264.172 )

V=0.03348 gallons

Step 2:

Determine the distance travelled by the special vehicle named “Micro joule” runs with ethanol.

L=C*V    .......... (3)

Here,  is the rate of consumption of ethanol by Micro joule.

Substitute 10,705 mi/gallons  for C and 0.03348 gallons  for .

By using eq. 3.

L= 10750*0.03348

L=358.416 mi.

Convert the distance travelled by Micro joule from miles to kilometres

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L = 576.813 km

Thus, the distance travelled by Micro joule is 576.813 km .

4 0
3 years ago
A. What frequency is received by a person watching an oncoming ambulance moving at 115 km/h and emitting a steady 753 Hz sound f
nasty-shy [4]

Answer:

A)828.8Hz

B)869.2Hz

Explanation:

Here is a complete question;

What frequency is received by a person watching an oncoming ambulance moving at 115 km/h and emitting a steady 753 Hz sound from its siren? Speed of sound is 345m/s

b. What frequency does she receive after the ambulance has passed?

Vs= speed of the ambulance

, We convert to m/s for unit consistency

= 115 km/h= 115km× 1000m/1m × 1hr/3600s= 31.94m/s

Dopler effect is when observed frequency of wave changes with respect to the source or when observed moves relative to transmitting medium can be expressed as

f'=[ (v + vo)/(v- vs)]*f

=[ (v )/(v- vs)]*f

The sign vo and vs depends on vthe direction of the velocity

f= frequency of ambulance siren= 753Hz

v= speed of sound in air= 345m/s

Vo= speed of observer= 0

A) we are to determine the f' of ambulance as heard by person as ambulance approaching.

To find the frequency f' observed by the person we use the expresion below

Then substitute the values

f'=[ (v )/(v- vs)]*f

=[ (345)/(345-31.94)]×753

= 828.8Hz

B)What frequency does she receive after the ambulance has passed?

To find the frequency f' observed by the person we use the expresion below

Then substitute the values

f'=[ (v )/(v + vs)]*f

=[ (345)/(345 + 31.94)]×753

= 869.2Hz

=

4 0
2 years ago
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