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bixtya [17]
3 years ago
12

5.0 kg, with a bullet of mass 0.1 kg. The target was mounted on

Physics
1 answer:
kari74 [83]3 years ago
8 0

Answer:

306 m/s

Explanation:

Law of conservation of momentum

m1v1 + m2v2 = (m1+m2)vf

m1 is the bullet's mass so it is 0.1 kg

v1 is what we're trying to solve

m2 is the target's mass so it is 5.0 kg

v2 is the targets velocity, and since it was stationary, its velocity is zero

vf is the velocity after the target is struck by the bullet, so it is 6.0 m/s

plugging in, we get

(0.1 kg)(v1) + (5.0 kg)(0 m/s) = (0.1 kg + 5.0 kg)(6.0 m/s)

(0.1)(v1) + 0 = 30.6

(0.1)(v1) = 30.6

v1 = 306 m/s

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Answer:

The potential difference between the places is 0.3 V.

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Explanation:

Given

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Answer:

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Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 243 m/s

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Next, we shall determine the time taken for the cannon to get to the ground. This can be obtained as follow:

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s = 865.08 m

Thus, the cannon ball will impact the ground 865.08 m from the base of the cliff.

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