5.0 kg, with a bullet of mass 0.1 kg. The target was mounted on
1 answer:
You might be interested in
Answer:
A. 1.64 J
Explanation:
First of all, we need to find how many moles correspond to 1.4 mg of mercury. We have:
where
n is the number of moles
m = 1.4 mg = 0.0014 g is the mass of mercury
Mm = 200.6 g/mol is the molar mass of mercury
Substituting, we find
Now we have to find the number of atoms contained in this sample of mercury, which is given by:
where
n is the number of moles
is the Avogadro number
Substituting,
atoms
The energy emitted by each atom (the energy of one photon) is
where
h is the Planck constant
c is the speed of light
is the wavelength
Substituting,
And so, the total energy emitted by the sample is
Given that force is applied at an angle of 30 degree below the horizontal
So let say force applied if F
now its two components are given as
Now the normal force on the block is given as
now the friction force on the cart is given as
now if cart moves with constant speed then net force on cart must be zero
so now we have
so the force must be 199.2 N