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GREYUIT [131]
3 years ago
11

The attractive electrostatic force between the point charges 6.14×10−6 c and q has a magnitude of 0.845 n when the separation be

tween the charges is 9.26 m . part a find the sign and magnitude of the charge q.
Physics
1 answer:
Nataly [62]3 years ago
3 0
Coulomb's law states that F = k(q1)(q2)/r^2, where k = 9 x 10^9 N-m^2/C^2
Substituting the given values:

0.845 N = (9x10^9 N-m^2/C^2)(6.14x10^-6 C)(q) / (9.26^2)
q = 0.00131 = 1.31 x 10^-3 C

Since the force is attractive, the point charges must be of opposite signs, and q is negatively charged (-1.31 x 10^-3 C).
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5 0
4 years ago
this event is the result of a sudden vertical offset in the ocean floor and is most often the result of plate movement on the oc
MissTica

Answer: Tsunami.

Explanation :

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3 years ago
A support crossbeam on a high speed train is made from a titanium rod that has a length of 0.650m when measured by an observer o
Vilka [71]

Answer:

A) The crossbeam is moving relative to the observer on the platform so the height appears contracted.

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3 0
3 years ago
Elsie is finishing second grade. If she goes to school 147 day per year and she have 10 years of school left, how many days of s
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Hopefully this helps you :)

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6 0
3 years ago
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Answer:

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