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Alex777 [14]
3 years ago
10

A proton accelerates from rest in a uniform electric field of 630 N/C. At one later moment, its speed is 1.50 Mm/s (nonrelativis

tic because v is much less than the speed of light). (a) Find the acceleration of the proton.
Physics
1 answer:
Vlad1618 [11]3 years ago
8 0

Answer:

the acceleration of the proton is 6.025 x 10¹⁰ m/s².

Explanation:

Given;

magnitude of electric field, E = 630 N/C

final speed of the proton, v = 1.5 M m/s = 1.5 x 10⁶ m/s

charge of proton, Q = 1.6 x 10⁻¹⁹ C

mass of proton, m = 1.673 x 10⁻²⁷ kg

The force experienced by the proton is calculated as;

F = ma = EQ\\\\a = \frac{EQ}{m} \\\\a = \frac{(630)(1.6\times 10^{-19})}{1.673 \times 10^{-27}} \\\\a = 6.025 \times 10^{10} \ m/s^2

Therefore, the acceleration of the proton is 6.025 x 10¹⁰ m/s².

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A boxer hits a punching bag with a force. Describe what happens.
Anna35 [415]

The punching bag applies the same amount of force to the boxer’s hand.   (C)

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3 years ago
What is the number of significant digits in the measurement 104.100 m?
Oksana_A [137]

Answer:

6

6 significant digits

Explanation:

Number of significant digits of a number are the number of digits that carry a relevant contribution to the measurement.

For the case above;

104.100

rule - all digits to the right of the decimal of any number equal or greater than 1 will count as a significant digit.

104.100 --- .100 ( the three digits counts)

And since the the digits to the left are none zero digits, so they all count as significant digits.

104.100 --- 104 ( the three digits counts)

The total number of significant digits,

Since all the digits of the number 104.100 will count as a significant digit.

The number of significant digits is equal to the number of digits in the number.

N = 6

6 significant digits

7 0
3 years ago
An unwary football player collides with a padded goalpost while running at a velocity of 7.50 m/s and comes to a full stop after
frez [133]

Answer:

(a) the deceleration of the player is -80.36 m/s²

(b) the time the collision last is 0.093 s

Explanation:

Given;

Initial velocity of the football player, u = 7.50 m/s

Final velocity of the football player, v = 0

distance traveled = compression of the pad, s = 0.35 m

Part (a) the deceleration of the player

v² = u² + 2as

0 = 7.5² + (2 x 0.35)a

0 = 56.25 + 0.7a

- 56.25 = 0.7a

a = -56.25 / 0.7

a = -80.36 m/s²

Part (b) the time the collision last

v = u + at

t = (v - u)/a

t = (0 - 7.5)/ -80.36

t = - 7.5 / -80.36

t = 0.093 s

7 0
3 years ago
A woman standing before a cliff claps her hands, and 2.8s later she hears the echo. How far away is the cliff? The speed of soun
ella [17]

Answer:

480.2 m

Explanation:

The following data were obtained from the question:

Speed of sound (v) = 343 m/s.

Time (t) = 2.8 s

Distance (x) of the cliff =?

The distance of the cliff from the woman can be obtained as follow:

v = 2x /t

343 = 2x /2.8

Cross multiply

2x = 343 × 2.8

2x = 960.4

Divide both side by the coefficient of x i.e 2

x = 960.4/2

x = 480.2 m

Therefore, the cliff is 480.2 m away from the woman.

4 0
3 years ago
Why are the nuclei of the heavier elements radioactive and not the lighter elements of nuclei?
KatRina [158]

Answer:

becouse most of nuclear elements are heave

Explanation:

6 0
3 years ago
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