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Alchen [17]
3 years ago
6

A batter swings and hits a pitched baseball far over the left field wall. at the moment the baseball contacts the bat, which obj

ect exerts a larger force
Physics
1 answer:
Lyrx [107]3 years ago
7 0
The baseball bat not the baseball
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In the formula vy = ayt, what is the value of ay for an object in projectile motion?
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An object is moving across a surface, but it is not gain or lose speed. Which best describes the objects force?
raketka [301]

Answer:

Gravity. An object is moving across a surface, but it does not gain or lose speed.

Explanation:

The basic idea. Physicists see gravity as one of the four fundamental forces that govern the universe, alongside electromagnetism and the strong and weak nuclear forces.

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PLS SHOW WORK !!!!!!! ASAP
Lynna [10]

Answer:

1- For the track B. The potential energy is the same for the two cars, but because of the slope of the track, the car B earn kinetic energy faster. The gravitation acceleration of the cars will be g•sinθ, and the angle of the track B will have a bigger value for sinθ

2- The conservation of energy applies because the roller coaster is a closed track. When a car climb the track, it earn GPE, which is given by mgh, when it get down in the track, it transform GPE in KE, which is given in 1/2mv².

3-

Position of car (m) GPE KE GPE + KE

top (30m) 60000 0 60000

bottom (0m) 0 60000 60000

halfway down (15m) 30000 30000 60000

three-quarters way down 15000 45000 60000

4 0
3 years ago
A 0.150 kg baseball has 118 j of KE. how fast is the ball moving?(unit=m/s)
MrRissso [65]

Answer:

Explanation 118 = (1/2) * 0.15 * v² 118 = 0.075 * v² v² = 1573.33 m/s ... since KE = m/2*V^2 , then : V = √2KE/m = √20*118/1.5 = 39.67 m//sec ( 142.8 km/h ; 88.75 mph).:

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A spherical drop of water carrying a charge of 42 pC has a potential of 620 V at its surface (with V = 0 at infinity). (a) What
iren [92.7K]

Answer:

0.0006091222 m

Explanation:

q = Charge = 42 pC

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Electric potential is given by (at r = R)

V=\dfrac{q}{4\pi\epsilon R}\\\Rightarrow R=\dfrac{q}{4\pi\epsilon V}\\\Rightarrow R=\dfrac{42\times 10^{-12}}{4\pi\times 8.85\times 10^{-12}\times 620}\\\Rightarrow R=0.0006091222\ m

The radius of the drop is 0.0006091222 m

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3 years ago
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