Every choice has a positive or negative consequence. <br> a. True<br> b. False

What are the three most important types of units in radiobiology? Explain the meaning of each.

Rom4ik [11]

Answer:

Most adverse health effects of radiation exposure may be grouped in two general categories:

deterministic effects (harmful tissue reactions) due in large part to the killing/ malfunction of cells following high doses; and

stochastic effects, i.e., cancer and heritable effects involving either cancer development in exposed individuals owing to mutation of somatic cells or heritable disease in their offspring owing to mutation of reproductive (germ)

4 0

3 years ago

5. A 4.00 kg object slides down a frictionless inclined plane with an acceleration of 3.00 m/s2. What is the angle of the inclin

Kazeer [188]

Answer:

The angle of the incline above horizontal is 17.81 degrees.

Explanation:

Given that,

Mass of the object, m = 4 kg

Acceleration of the object above the incline, $a=3\ m/s^2$

We need to find the angle of the incline above horizontal. The net force acting on the object along the incline is given by :

$F_{net}=mg\ sin\theta$

$ma=mg\ sin\theta$

$a=g\ sin\theta$

$sin\theta=\dfrac{a}{g}$

$sin\theta=\dfrac{3}{9.8}$

$\theta=17.81^{\circ}$

So, the angle of the incline above horizontal is 17.81 degrees. Hence, this is the required solution.

5 0

4 years ago

one of the ways, covered in the article and in class, that we charged an object was rubbing it against carpet on the floor true

astraxan [27]

Answer:

It is possible to statically charge objects by rubbing it against carpet fibers, but I'm not sure if that was in the article that you read.

Explanation:

Static charge can build up via carpet fibers.

5 0

3 years ago

identify the action reaction forces in each picture the first picture is done for you write your answer on a separate sheet of p

xxMikexx [17]

Newton's Third Law of Motion states that for every action there must exist an equal but opposite reaction.

This ultimately implies that, Newton's Third Law of Motion is a law based on action-reaction force pairs.

In this exercise, you're required to identify the action-reaction forces in the attached picture.

Under condition A, a boy is leaning against a wall;

The force being exerted by the boy on the wall is a force of action.

The force being exerted by the wall on the boy is a force of reaction.

Under condition B, a boy is jumping off a diving board.

The force being exerted by the feet of the boy on the diving board is a force of action.

The force being exerted by the diving board on the feet of the boy is a force of reaction.

Under condition C, a nail is being hammered into the wall.

The force being exerted by the hammer on the nail is a force of action.

The force being exerted by the nail on the hammer is a force of reaction.

Under condition D, a man is walking on a ground (floor).

The force being exerted by the foot of the man on the ground (floor) is a force of action.

The force being exerted by the ground (floor) on the foot of the man is a force of reaction.

Under condition E, a boy is holding a ball;

The force being exerted by the hand of the boy on the ball is a force of action.

The force being exerted by the ball on the hand of the boy is a force of reaction.

4 0

3 years ago

Water drips from the nozzle of a shower onto the floor 189 cm below. The drops fall at regular (equal) intervals of time, the fi

laiz [17]

Answer:

0.83999 m

0.20999 m

Explanation:

g = Acceleration due to gravity = 9.81 m/s² = a

s = 189 cm

$s=ut+\frac{1}{2}at^2\\\Rightarrow 1.89=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{1.89\times 2}{9.81}}\\\Rightarrow t=0.62074\ s$

When the time intervals are equal, if four drops are falling then we have 3 time intervals.

So, the time interval is

$t'=\dfrac{t}{3}\\\Rightarrow t'=\dfrac{0.62074}{3}\\\Rightarrow t'=0.206913\ s$

For second drop time is given by

$t''=2t'\\\Rightarrow t''=2\times 0.2069133\\\Rightarrow t''=0.4138266\ s$

Distance from second drop

$s=ut+\dfrac{1}{2}at^2\\\Rightarrow y''=ut''+\dfrac{1}{2}at''^2\\\Rightarrow s=0\times t+\dfrac{1}{2}\times 9.81\times 0.4138266^2\\\Rightarrow s=0.839993\ m$

Distance from second drop is 0.83999 m

Distance from third drop

$s=ut+\dfrac{1}{2}at^2\\\Rightarrow y''=ut'+\dfrac{1}{2}at'^2\\\Rightarrow s=0\times t+\dfrac{1}{2}\times 9.81\times 0.206913^2\\\Rightarrow s=0.20999\ m$

Distance from third drop is 0.20999 m

6 0

4 years ago

Every choice has a positive or negative consequence. a. True b. False