G as in grams? Because what I got is 0.0602 from my calculator. So I'm not sure if that's what you are looking for.
Heat released from combustion is calculated by multiplying the amount of substance being burned with its heat of combustion. From this, we can calculate the mass needed from the system above. The calculation is as follows:
-543 kJ = x x -1320 kJ/mol
x = 0.411 mol
Mass of x = 0.411 x 71.83 g/mol
Mass of x = 29.55 g
For every action<span>, </span>there<span> is </span>an<span> equal and </span>opposite reaction<span>.</span>
Answer:
No object rises a greater height. They both rise the same height.
Explanation:
Since the kinetic energy = work done by gravity
1/2mv² = mgh
h = v²/2g where h is the height and v the speed.
Since the speed is the same for both objects, the height moved is the same since the expression for the height moved is independent of their masses but dependent on their speeds.
So, no object rises a greater height. They both rise the same height.
Answer:
Corresponding raft speed = -0.875 m/s (the minus sign indicates that the raft moves in the direction opposite to the diver)
Explanation:
Law of conservation of momentum gives that the momentum of the diver and the raft before the dive is equal to the momentum of the diver and the raft after the dive.
And since the raft and the diver are initially at rest, the momentum of the diver after the dive is equal and opposite to the momentum experienced by the raft after the dive.
(Final momentum of the diver) + (Final momentum of the raft) = 0
Final Momentum of the diver = (mass of the diver) × (diving velocity of the diver)
Mass of the diver = 73 kg
Diving velocity of the diver = 5.54 m/s
Momentum of the diver = 73 × 5.54 = 404.42 kgm/s
Momentum of the raft = (mass of the raft) × (velocity of the raft)
Mass of the raft = 462 kg
Velocity of the raft = v
Momentum of the raft = 462 × v = (462v) kgm/s
404.42 + 462v = 0
462v = -404.42
v = (-404.42/462) = -0.875 m/s (the minus sign indicates that the raft moves in the direction opposite to the diver)
Hope this Helps!!!
