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s2008m [1.1K]
3 years ago
15

Draw the two chair conformations of cis 1 chloro 2 methylcyclohexane

Chemistry
1 answer:
Mrrafil [7]3 years ago
6 0
In chair conformations of cyclohexane, Cl group is on the first C and methyl group is on the second C. In the cis conformation both groups should be in the same orientation, either both side chains should be up and up or down and down. In this figure its up and up. 
2 figures are drawn as when the chair conformation flips, the axial groups become equatorial and equatorial groups become axial. But they remain as up or down .
When A flips to B, Cl goes from axial to equatorial and CH3 goes from equatorial to axial but both remain up.

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An automobile tire contains air at 320.×103 Pa at 20.0 ◦C. The stem valve is removed and the air is allowed to expand adiabatica
NISA [10]

Answer:

6.15.3 k

Explanation:

From the question we can see that

q = 0,  Δu = w

Then,

T_f = \frac{C_{V,m}+RP_{ext}P_i}{C_{V,m}+RP_{ext}P_f} T_i

putting values wet

=\frac{2.5\times 8.314+8.314\left(10^5\right)\left(3.20\times 10^5\right)}{2.5\times 8.314+\left(8.314\right)\left(10^5\right)\left(10^5\right)}\times \:293

T_f = 615.3 K

6 0
3 years ago
Which chemical or physical change is a endothermic process
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Melting, vaporization, boiling, and sublimation.
5 0
2 years ago
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Radiation is a measure of average kinetic energy of particles in an object true or false ​
laila [671]

Answer:false

Explanation:

4 0
3 years ago
How many milliliters of 0.100 m naoh are required to neutralize 9.00 ml of 0.0500 m hcl?
BabaBlast [244]
V  ( NaOH ) = mL ?

M ( NaOH ) = 0.100 M

V ( HCl ) = 9.00 mL / 1000 => 0.009 L

M ( HCl ) = 0.0500 M

number of moles HCl:

n = M x V

n = 0.009 x 0.0500 => 0.00045 moles HCl

mole ratio:

<span>HCl + NaOH = NaCl + H2O
</span>
 1 mole HCl ---------------- 1 mole NaOH
 0.00045 moles HCl ----- ??

0.00045 x 1 / 1 => 0.00045 moles of NaOH

M = n / V

0.100 = 0.00045 / V

V = 0.00045 / 0.100

V = 0.0045 L

1 L ------------ 1000 mL
0.0045 L ----- ??

0.0045 x 1000 / 1 => 4.5 mL of NaOH



6 0
3 years ago
What is the volume of a sample if the density is 2.35 g/mL and the mass is 33.67 g?
lawyer [7]
  • Density=2.35g/mL
  • Mass=33.67g

\\ \star\sf\longmapsto Density=\dfrac{Mass}{Volume}

\\ \star\sf\longmapsto Volume=\dfrac{Mass}{Density}

\\ \star\sf\longmapsto Volume=\dfrac{33.67}{2.35}

\\ \star\sf\longmapsto Volume=14.32mL

6 0
2 years ago
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