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Anettt [7]
3 years ago
14

NEED HELP ASAP!!!!

Physics
1 answer:
podryga [215]3 years ago
6 0
The answer is B
I rhink
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When a slice of buttered toast is accidentally pushed over the edge of a counter, it rotates as it falls. If the distance to the
Ksenya-84 [330]

Answer: 4.83rad/s and 14.50 rad/s

Explanation:

The distance from the center to the floor d = 52cm = 0.52m

Rotation is less than 1 rev

The toast rotates at a constant angular speed

Using kinematic d = Vit + 1/2gt^2

d = 0+1/2gt^2

t = (2d/g) square root

t = square root of 2× 0.52/ 9.8

t = 0.325s

The toast is accidentally pushed over the edge of the centre with butter side up, then the toast rotates as it falls . If the toast hits the ground and topples, the smallest angle will be less than 1/4 rev with correspondence to the smallest angular speed

Wmin = change in tetha/ change in time

= 0.25 rev/ change in t

= 0.25×2pii / change in t

= 0.5pii/0.325

= 0.5×3.142/0.325

= 4.83 rad/s

The toast is accidentally pushed over the edge of the centre with butter side up, then the toast rotates as it falls . If the toast hits the ground and topples, the maximum angle will be less than 3/4 rev with correspondence to the maximum angular speed

Wmax = change in tetha/ change in time

= 0.75 rev/ Change in time

= 0.75 ×2pii/change in tetha

= 1.5pii/0.325

= 1.5 ×3.142/0.325

= 14.50 rad/s

Note the following

Vi is the initial speed of the toast which is zero because it was initially at rest

t is the time taken for the toast to hit the floor

g is the gravitational acceleration

d is the distance between the counter and the floor. There is an attachment for you as well.

Thanks

5 0
3 years ago
Help me with number 8 please :(
stiks02 [169]
Is there an answer key? with all words on it,
5 0
3 years ago
A typical laboratory centrifuge rotates at 3700 rpm . Test tubes have to be placed into a centrifuge very carefully because of t
Alexus [3.1K]

Answer:

Explanation:

acceleration of test tube

= ω² R

= (2πn)² R

= 4π²n²R

n = no of rotation per second

= 3700 / 60

= 61.67

R = .10 m

acceleration

= 4π²n²R

= 4 x 3.14² x 61.67² x .10

= 14999 N Approx

3 0
3 years ago
Answer question quick
Anettt [7]

Answer:

Yes , insulation has no role

5 0
3 years ago
Pls help A car starts from rest and gains a velocity of 20m/s in 10 seconds calculate its acceleration and the distance covered
Soloha48 [4]

Answer:

\boxed{\sf Acceleration \ (a) = 2 \ m/s^{2}}

\boxed{\sf Distance \ covered \ (s) = 100 \ m}

Given:

Initial velocity (u) = 0 m/s

Final velocity (v) = 20 m/s

Time taken (t) = 10 sec

To Find:

(i) Acceleration (a)

(ii) Distance covered (s)

Explanation:

\sf (i) \ From \ 1^{st} \ equation \ of \ motion:

\sf \implies v = u + at

\sf \implies 20 = 0 + a(10)

\sf \implies 10a = 20

\sf \implies \frac{10a}{10}  =  \frac{20}{10}

\sf \implies a = 2 \: m/ {s}^{2}

\sf (ii) \ From \ 2^{nd} \ equation \ of \ motion:

\sf \implies s = ut +  \frac{1}{2} a {t}^{2}

\sf \implies s = (0)(10) +  \frac{1}{2}  \times 2 \times  {(10)}^{2}

\sf \implies s =  \frac{1}{ \cancel{2}}  \times  \cancel{2} \times  {(10)}^{2}

\sf \implies s =  {10}^{2}

\sf \implies s = 100 \: m

6 0
3 years ago
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