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2 years ago

Two rods of mass m, length L are stuck together to form an X shape and spun around the center. What is the rotational inertia

1 answer:

4 0

The shapes of XLMA ain’t digestive monkeys monkeys have a digestive system of a hippopotamus Mr. hippopotamus want to eat I am yams or sweet potatoes they are potatoes are sweeter than the normal potato

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Force is a vector because it has both ___

scoray [572]

Answer:

C. Size and Direction

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2 years ago

The 88-lb force P is applied to the 210-lb crate, which is stationary before the force is applied. Determine the magnitude and d

Marina86 [1]

Answer:

$F=-88Ib$

Explanation:

From the question we are told that:

Force P=88Ib

Mass of crate M_c=210Ib

Generally the equation for Frictional force F is mathematically given by

$Friction\ force (f) = friction\ coefficient\ (u) * Normal\ reaction (N)$

$F=u*N$

with $\mu =0.47$

$F=98.7Ib$

Therefore since Static Friction supersedes applied force body remains at rest.

Frictional force =88Ib (negative)

$F=-88Ib$

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2 years ago

This roadblock is present when a person assumes they know what the other person is going to say and they are too impatient to wa

Westkost [7]

The answer is mindreading. Have a great day :)

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2 years ago

Read 2 more answers

A certain spring stores 10.0J of potential energy when it isstretched by 2.00cm from its equilibrium position.How much potential

qaws [65]

Answer:

Answered

Explanation:

x= 0.02 m

E_p= 10.0 J

E_p= 0.5kx^2

10= 0.5k(0.02)^2

solving we get

K= 50.0 N/m

Now

E'_p= 0.5kx'^2

E'_p= 0.5×50×(0.04)^2

E'_p=40 J

b) potential energy is a scalar quantity and it only depends magnitude and not direction so it will remain same in compression and expansion both

c) 20 J = 0.5×50,000×x^2

solving

x= 0.028 m

d) k is 50.0 N/m from above calculation

3 0

3 years ago

An infant's toy has a 120 g wooden animal hanging from a spring. If pulled down gently, the animal oscillates up and down with a

Morgarella [4.7K]

Answer:

0.37 m

Explanation:

The angular frequency, ω, of a loaded spring is related to the period, T, by

$\omega = \dfrac{2\pi}{T}$

The maximum velocity of the oscillation occurs at the equilibrium point and is given by

$v = \omega A$

A is the amplitude or maximum displacement from the equilibrium.

$v = \dfrac{2\pi A}{T}$

From the the question, T = 0.58 and A = 25 cm = 0.25 m. Taking π as 3.142,

$v = \dfrac{2\times3.142\times0.25\text{ m}}{0.58\text{ s}} = 2.71 \text{ m/s}$

To determine the height we reached, we consider the beginning of the vertical motion as the equilibrium point with velocity, v. Since it is against gravity, acceleration of gravity is negative. At maximum height, the final velocity is 0 m/s. We use the equation

$v_f^2 = v_i^2+2ah$

$v_f$ is the final velocity, $v_i$ is the initial velocity (same as v above), a is acceleration of gravity and h is the height.

$h = \dfrac{v_f^2 - v_i^2}{2a}$

$h = \dfrac{0^2 - 2.71^2}{2\times-9.81} = 0.37 \text{ m}$

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2 years ago