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S_A_V [24]
3 years ago
13

A cyclotron is to accelerate protons to an energy of 5.4 MeV. The superconduction electromagnet of the cyclotron produces a 2.9T

magnetic field perpendicular to the proton orbits.When the protons have acheived a kinetic energy of 2.7 MeV, what is the radius of their circular orbit and what is their angular speed?
Physics
1 answer:
mart [117]3 years ago
3 0
<h3><u>Answer;</u></h3>

Radius = 0.0818 m

Angular velocity = 2.775 × 10^7 rad/sec

<h3><u>Explanation;</u></h3>

The mass of proton m=1.6748 × 10^-27 kg;  

Charge of electron e= 1.602 × 10^-19 C;  

kinetic energy E= 2.7 MeV

                          = 2.7 × 10^6 × 1.602 × 10^-19 J;

                          = 4.32 × 10^-13 Joules

But; K.E =0.5m*v^2,

Hence v=√(2K.E/m)

Velocity = 2.27 × 10^7 m/s

Angular velocity, ω = v/r

Therefore; V = ωr

Hence; V = √(2K.E/m) = ωr

r= √(2E/m)/w = √E*√(2*m)/(eB)

  = √E * √(2×1.6748×10^-27)/(1.602×10^-19 ×2.9)

but E =  4.32 × 10^-13 Joules

  r = 0.0818 m

Angular speed

Angular velocity, ω = v/r , where r is the radius and v is the velocity

Therefore;

Angular velocity = 2.27 × 10^7 / 0.0818 m

                            = 2.775 × 10^7 rad /sec

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Given parameters:

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Unknown:

time  = ?

Solution:

Velocity is displacement divided by time.

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      Displacement  = velocity x time

Input the parameters:

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Lyrx [107]
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Explanation:

1) The second law of Newton gives the definition and formula to calculate the net force:

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2) From that, when you know the net force acting of the object and its mass, you can solve for the acceleration:

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acceleration = 50 N / 5 kg = 10 m/s^2, which is the answer.
8 0
3 years ago
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Salsk061 [2.6K]

Answer: 12,600,000Cm

Explanation:

From the data's;

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Answer:

The correct option is (d).

Explanation:

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8 0
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