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Anit [1.1K]
3 years ago
11

To make 1.00 L of 1.00 M NaOH solution, what mass of NaOH needs to be weighed out?

Chemistry
2 answers:
kifflom [539]3 years ago
3 0

Answer: 2.35

Explanation:

sleet_krkn [62]3 years ago
3 0

Answer:

About 40 grams

Explanation:

The first step is to find the molar mass of NaOH. This can be done by combining the molar mass of all of the elements inside of it. Na, or sodium, has a molar mass of about 23. Oxygen has a molar mass of about 16, and hydrogen has a molar mass of about 1. Adding all of these together, you get a total molar mass of 40. This means that a single mole of NaOH weighs 40 grams, which is the mass of NaOH that needs to be weighed out. Hope this helps!

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Alkali metals are known for being some of the most reactive metals. This is due in part to their larger atomic radii and low ionization energies. They tend to donate their electrons in reactions and often have an oxidation state of +1. These metals are characterized as being extre
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25 °C = ________ K <br><br> which one <br> 298<br> 0<br> 33 <br> 197
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Answer:

298

hope this helps

have a good day :)

Explanation:

5 0
3 years ago
Read 2 more answers
The density of no2 in a 4.50 l tank at 760.0 torr and 25.0 °c is ________ g/l.
kap26 [50]
From  ideal  gas  equation   that   is   PV=nRT
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7 0
2 years ago
Read 2 more answers
In air, a silver object can tarnish due to the reaction of silver with hydrogen sulfide, a gas found in the air as a result of c
cluponka [151]

Answer:

The coefficient of Ag is 2.

Explanation:

___Ag (s) + ___H₂S (g) ⇒ ___ Ag₂S (s) + ___ H₂(g)

The Law of Conservation of Matter is also called the law of conservation of mass or the Law of Lomonósov-Lavoisier. This law postulates that "the mass is not created or destroyed, only transformed." This means that the reagents interact with each other and form new products with physical and chemical properties different from those of the reagents because the atoms of the substances are ordered differently. But the amount of matter or mass before and after a transformation (chemical reaction) is always the same, that is, the quantities of the masses involved in a given reaction must be constant at all times, not changing in their proportions when the reaction ends.

In others words, the law of conservation of matter states that since no atom can be created or destroyed in a chemical reaction, the number of atoms that are present in the reagents has to be equal to the number of atoms present in the products.

Then, you must balance the chemical equation. For that, you must first look at the subscripts next to each atom to find the number of atoms in the equation. If the same atom appears in more than one molecule, you must add its amounts :

Left side: 1 Ag, 2 H and 1 S

Right side: 2 Ag, 2 H and 1 S

The coefficients located in front of each molecule indicate the amount of each molecule for the reaction. This coefficient can be modified to balance the equation, just as you should never alter the subscripts.

By multiplying the coefficient mentioned by the subscript, you get the amount of each element present in the reaction.  

You can see that the elements H and S are balanced because we have the same quantity on both sides of the reaction. Then you must balance the Ag, so the reaction is:

2 Ag (s) + 1 H₂S (g) ⇒ 1 Ag₂S (s) + 1 H₂(g)

Now you have:

Left side: 2 Ag, 2 H and 1 S

Right side: 2 Ag, 2 H and 1 S

So, you have the same amount of each element to both of the reaction and this is balanced.

Then, <u><em>the coefficient of Ag is 2.</em></u>

7 0
3 years ago
Please help, with step by step work
natali 33 [55]

\qquad ☀️\pink{\bf{ {Answer  = \: \:   85.57g }}}

Molar mass of \bf Cu_2O

\qquad \twoheadrightarrow\sf 63.546 \times 2 +16

\qquad \pink{\twoheadrightarrow\bf 143.092 g}

<u>As we know</u>–

1 mol =\bf 6.02×10^{23} formula units

1 mol\bf Cu_2O = 143.092 g = \bf 6.02×10^{23}formula units

Henceforth –

\bf 3.60×10^{23} formula units \bf Cu_2O–

\qquad \sf :\implies \dfrac{143.092 \times3.60×10^{23  }}{6.02×10^{23}}

\qquad \sf :\implies \dfrac{143.092 \times3.60×\cancel{10^{23  }}}{6.02×\cancel{10^{23}}}

\qquad \pink{:\implies\bf 85.57 g}

5 0
2 years ago
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