Which of the following are in the correct order from smallest to largest?
1 answer:
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Explanation:
Expression to calculate thermal resistance for iron () is as follows.
where, = length of the iron bar
= thermal conductivity of iron
= Area of cross-section for the iron bar
Thermal resistance for copper () = \frac{L_{c}}{k_{c} \times A_{c}}[/tex]
where, = length of copper bar
= thermal conductivity of copper
= Area of cross-section for the copper bar
Now, expression for the transfer of heat per unit cell is as follows.
Q =
Putting the given values into the above formula as follows.
Q =
=
= 2.92 Joule
It is known that heat transfer per unit time is equal to the power conducted through the rod. Hence,
P =
Here, T is 1 second so, power conducted is equal to heat transferred.
So, P = 2.92 watt
Thus, we can conclude that 2.92 watt power will be conducted through the rod when it reaches steady state.
Answer:
(a) charge q=5.33 nC
(b) charge density σ=10.62 nC/m²
Explanation:
Given data
radius r=0.20 m
potential V=240 V
coulombs constant k=9×10⁹Nm²/C²
To find
(a) charge q
(b) charge density σ
Solution
For (a) charge q
As
For (b) charge density
As charge density σ is given as:
σ=q/(4πR²)
σ=(5.333×10⁻⁹) / (4π×(0.20)²)
σ=10.62 nC/m²