Let be the height of the building and thus the initial height of the ball. The ball's altitude at time
is given by
where is the acceleration due to gravity.
The ball reaches the ground when after
. Solve for
:
so the building is about 16 m tall (keeping track of significant digits).
Answer:
Velocity.
Explanation:
Projectile motion is characterized as the motion that an object undergoes when it is thrown into the air and it is only exposed to acceleration due to gravity.
As per the question, 'any change in the initial velocity of the projectile(object having gravity as the only force) would lead to a change in the range as well as the maximum height of the projectile.' To illustrate numerically:
Horizontal range: As per expression:
R= (*sin2θ)/g
the range depending on the square of the initial velocity.
Maximum height: As per expression:
H= ( *
θ
)/2g
the maximum distance also depends upon square of the initial velocity.
Ryan applied a force of 10N and moved a book 30 cm in the direction of the force. How much was the work done by Ryan?
<h2><u>Answer:</u><u>-</u></h2><h3>Given,</h3>=> Force applied by Ryan = 10N
=> Distance covered by the book after applying force = 30 cm
<h3>And,</h3>30 cm = 0.3 m (distance)
<h3>So,</h3>=> Work done = Force × Distance
=> 10 × 0.3
=> 3 Joules