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aev [14]
3 years ago
15

An industrial process makes calcium oxide by decomposing calcium carbonate. Which of the following is NOT needed to calculate th

e mass of calcium oxide that can be produced from 4.7 kg of calcium carbonate?
A. the balanced chemical equation

B. molar masses of the reactants

C. molar masses of the product

D. the volume of the unknown mass
Chemistry
2 answers:
Sedbober [7]3 years ago
7 0
An industrial process makes calcium oxide by decomposing calcium carbonate. Which of the following is NOT needed to calculate the mass of calcium oxide that can be produced from 4.7 kg of calcium carbonate?

Answer: Out of all the options presented above the one that is not needed to calculate the mass of calcium oxide that can be produced from 4.7 kg of calcium carbonate is answer choice D) The volume of unknown mass.

I hope it helps, Regards.
Alinara [238K]3 years ago
3 0
Based on the scenario, that is not needed to calculate the mass of the calcium oxide is : D. the volume of the unknown mass

In order to find out the mass of a product, you just need the mass of the reactants and the mass of the product

hope this helps
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Explanation:

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This means that
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6 0
3 years ago
A chemist dissolves 867. mg of pure barium hydroxide in enough water to make up 170. mL of solution. Calculate the pH of the sol
Ilya [14]

Answer: The pH of the solution is 11.2

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n = moles of solute

V_s = volume of solution in ml

moles of Ba(OH)_2 = \frac{\text {given mass}}{\text {Molar mass}}=\frac{0.867g}{171g/mol}=0.00507mol         (1g=1000mg)

Now put all the given values in the formula of molality, we get

Molarity=\frac{0.00507\times 1000}{170}

Molarity=0.0298

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

pOH=-\log [OH^-]

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According to stoichiometry,

1 mole of Ba(OH)_2 gives 2 mole of OH^-

Thus 0.0298 moles of Ba(OH)_2 gives =\frac{2}{1}\times 0.0298=0.0596 moles of OH^-

Putting in the values:

pOH=-\log[0.0596]=2.82

pH+pOH=14

pH=14-2.82

pH=11.2

Thus the pH of the solution is 11.2

8 0
3 years ago
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Answer:

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Explanation:

4 0
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Answer:

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5 0
3 years ago
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