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erica [24]
3 years ago
6

PLEASE HELP ASAP, I HAVE 10 MINUTES ;

Mathematics
1 answer:
Ilya [14]3 years ago
7 0

Answer:

Step-by-step explanation:

when 13 bought we find these inequalities

x + 12y < 7  no

2x + 11y < 7.5 no

3x + 10y < 8 no

4x + 9y < 8.5 no

5x + 8y >  9  yes

When 14 bought we find these inequalities

x + 13y < 7.5 no

2x + 12y < 8 no

3x + 11y < 8.5 no

4x + 10y > 9 yes  

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PLEASE HHELP!!! Bring the fraction:
Anna35 [415]

Answer:

\frac{b}{7a^2c} = \frac{5abc^2}{35a^3c^3}

\frac{a}{a - 4} = \frac{-a^2 - 4a}{16 -a^2}

Step-by-step explanation:

Given

\frac{b}{7a^2c}

Express the denominator as 35a^3c^3

To do this, we divide35a^3c^3 by the denominator

\frac{35a^3c^3}{7a^2c} = 5ac^2

So, the required fraction is:

\frac{b}{7a^2c} * \frac{5ac^2}{5ac^2}

\frac{5abc^2}{35a^3c^3}

Hence:

\frac{b}{7a^2c} = \frac{5abc^2}{35a^3c^3}

Given

\frac{a}{a - 4}

Express the denominator as 16 - a^2

Multiply the fraction a+4/a+4

So, we have:

\frac{a}{a - 4} * \frac{(a + 4)}{(a + 4)}

Apply difference of two squares to the denominator

\frac{a^2 + 4a}{a^2 - 16}

Take the additive inverse of the numerator and denominator

\frac{-(a^2 + 4a)}{-(a^2 - 16)}

\frac{-a^2 - 4a}{16 -a^2}

Hence:

\frac{a}{a - 4} = \frac{-a^2 - 4a}{16 -a^2}

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2 years ago
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yulyashka [42]

Answer:

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Step-by-step explanation:

let me know if this is right

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