Answer:
trial 1: % error = 3.546 %
trial 2: % error = 3.073 %
trial 3: % error = 0.946 %
Explanation:
- % error = ((ΔHi - ΔH) / ΔH) ×100
∴ ΔH = - 42.3 KJ/mol
trial 1:
∴ ΔH1 = - 43.8 KJ/mol
⇒ % error = ((-43.8 - ( -42.3 )) / ( -42.3 ))×100
⇒ % error = (0.03546)*100 = 3.546 %
trial 2:
∴ ΔH2 = - 41.0 KJ/mol
⇒ % error = ((-42.3 - ( -41.0 )) / ( -42.3 ))×100
⇒ % error = (0.03073)*100 = 3.073%
trial 3:
∴ ΔH3 = - 42.7 KJ/mol
⇒ % error = ((-42.7 - ( -42.3 )) / ( -42.3 ))×100
⇒ % error = (9.456 E-3)*100 = 0.946 %
The answer is 28% as u find the molar mass of cu and divide it by the total molar mass
17.24 grams of ZNO and 6.87 of grams of HCI
Answer:
A) 0.20 cm³
B) 49.7 m²
C) 99.99%
D) 17.7 mg
Explanation:
A) The density of a material represents the mass that it occupies in a "piece" of volume. Thus, the density (d) is the mass (m) divided by the volume (v):
d =m/v
If the mass is 40.0 mg = 0.04 g, and the density is 0.20 g/cm³, the volume is:
0.20 = 0.04/v
v = 0.04/0.20
v = 0.20 cm³
B) The surface area (S) is the are that is presented in each gram of the material, so, it's the area (a) divided by the mass (m):
S = a/m
If the mass is 40.0 mg = 0.04 g, and the surface area is 1242 m²/g, so:
1242 = a/0.04
a = 49.7 m²
C) The percent of mercury removed is the mass removed divided by the initial mass, this multiplied by 100%. The mass removed is the initial mass (m0) less the final mass (m), so:
%removed = [(7.748 - 0.001)/7.748] *00%
%removed = 99.99%
D) The final mass of the spongy material is it mass (10 mg) plus the mass removed of the mercury (7.748 - 0.001 = 7.747 mg), so:
m = 10 + 7.747
m = 17.747 mg
m = 17.7 mg