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hichkok12 [17]
3 years ago
5

A 83 kg man is resting on the roof top of his house. If he has a potential energy of

Physics
2 answers:
Anvisha [2.4K]3 years ago
4 0

Answer:

It would be 70m

Explanation:

I hope this helps!

ivann1987 [24]3 years ago
3 0
60 m because that’s the top energy of the roof
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A 0.15 kg baseball falls to the ground with an acceleration of 9.8 m/s2. What is the weight of the baseball?
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The weight of the baseball is 
B. 1.49 N
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Explain how the property of density is applied and used in the real world
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Answer:

One well-known application of density is determining whether or not an object will float on water. If the object's density is less than the density of water, it will float; if its density is less than that of water, it will sink. ... In fact, submarines dive below the surface of the water by emptying their ballast tanks.

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2 years ago
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You are using a small telescope to view two closely spaced light bulbs located a mile away. Each light bulb is emitting blue lig
Juliette [100K]

Answer:

Explanation:

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resolving power of telescope ∝  1 / λ

Higher the resolving power closer the object that can be looked separately.

Wave length of blue light is shorter than that of red light so resolving power in case of blue light will be higher. So we have better chance of distinguishing separate bulbs when color light is blue.

5 0
4 years ago
I need help with this question how to solve it for Brass and Cooper
Ksenya-84 [330]

Take into account that density and relative density are given by:

\begin{gathered} \text{density}=\text{ mass/volume} \\ \text{relative density = density/density of water} \end{gathered}

Take into account that the volume associated to each of the given sustances in the table is determined by the Level Difference (because it is the change in the volume of the water of the recipient in which the substance is immersed).

The density of water in kg/m^3 is 1000 kg/m^3.

Due to the density must be given in kg/m^3, it is necessary to express the volumes of the table in m^3 and mass in kg, then, consider the following conversion factor:

1 m^3 = 1000000 ml

1 kg = 1000 g

Then, you obtain the following results:

Brass:

\begin{gathered} 53.2g\cdot\frac{1kg}{1000g}=0.0532kg \\ 6ml\cdot\frac{1m^3}{1000000ml}=0.000006m^3 \\ \text{density}=\frac{0.0532kg}{0.000006m^3}\approx8866.67\frac{kg}{m^3} \\ \text{relative density=}\frac{(\frac{8866.66kg}{m^3})}{(1000\frac{kg}{m^3})}\approx8.87 \end{gathered}

Cooper:

\begin{gathered} 57.4g=0.0574kg \\ 6ml=0.000006m^3 \\ \text{density}=\frac{0.0574kg}{0.000006m^3}\approx9566.67\frac{kg}{m^3} \\ \text{relative density=}\frac{\frac{9566.67kg}{m^3}}{1000kg}=9.57 \end{gathered}

3 0
1 year ago
How high would you have to go in the atmosphere for half of the mass of air to be below you?
AnnZ [28]
5.6 km exact height of the atmosphere has no real meaning, air progressively gets thinner and thinner the higher one travels upwards
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3 years ago
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