d. 49.0 m/s
<em><u>this</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>your</u></em><em><u> </u></em><em><u>answer</u></em><em><u>. </u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>OK</u></em><em><u>. </u></em><em><u>.</u></em><em><u>.</u></em>
<em><u>please</u></em><em><u> </u></em><em><u>mark</u></em><em><u> </u></em><em><u>me</u></em><em><u> </u></em><em><u>as</u></em><em><u> </u></em><em><u>brainliest</u></em><em><u>. </u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
<em><u>follow</u></em><em><u> </u></em><em><u>me</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>my</u></em><em><u> </u></em><em><u>friend</u></em><em><u>. </u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Explanation:
Newton's second law:
∑F = ma
277 N − 245 N = (25 kg) a
a = 1.28 m/s²
Answer:
The magnitude of each charge is 
Explanation:
Suppose the two point charges are separated by 6 cm. The attractive force between them is 20 N.
We need to calculate the magnitude of each charge
Using formula of force

Where, q = charge
r = separation
Put the value into the formula




Hence, The magnitude of each charge is 
Answer:
The force exerted by the rope on her arms is 273.7 N = 0.274 kN
Explanation:
Step 1: Data given
Mass of the ice skater = 55.6 kg
Velocity = 1.73 m/s
She then moves in a circle of radius 0.608 m around the pole.
Step 2:
Force exterted by the horizontal rope is the centripetal force acting on theice skater:
Fc = M*ac
⇒ with ac = v²/r
Fc = M * v²/r
Fc = 55.6 * 1.73²/0.608
Fc =273.69 N
The force exerted by the rope on her arms is 273.7 N = 0.274 kN
Answer:
d) When the diaphragm pushes upward, it decreases the volume of the lungs, pushing air out.
Explanation:
the relaxed diaphragm muscle is dome-shaped, the contracted muscle is horizontal.