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3 years ago

12

Which formula is used to calculate the mass of an object if the force and acceleration are known? m = Fa m = m = m = F – a

2 answers:

SOVA2 [1]3 years ago

7 0

I'm pretty sure it is m = Fa

tekilochka [14]3 years ago

3 0

Answer:

M=F/a is the answer

Explanation:

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A thermistor is placed in a 100 °C environment and its resistance measured as 20,000 Ω. The material constant, β, for this therm

Karo-lina-s [1.5K]

Answer:

the thermistor temperature = $325.68 \ ^0 \ C$

Explanation:

Given that:

A thermistor is placed in a 100 °C environment and its resistance measured as 20,000 Ω.

i.e Temperature

$T_1 = 100^0C\\T_1 = (100+273)K\\\\T_1 = 373\ K$

Resistance of the thermistor $R_1 =$ 20,000 ohms

Material constant $\beta$ = 3650

Resistance of the thermistor $R_2$ = 500 ohms

Using the equation :

$R_1 = R_2 \ e^{\beta} (\frac{1}{T_1}- \frac{1}{T_2})$

$\frac{R_1}{ R_2} = \ e^{\beta} (\frac{1}{T_1}- \frac{1}{T_2})$

Taking log of both sides

$In \ \frac{R_1}{ R_2} = In \ \ e^{\beta} (\frac{1}{T_1}- \frac{1}{T_2})$

$In \ \frac{R_1}{ R_2} = {\beta} (\frac{1}{T_1}- \frac{1}{T_2})$

$\frac{ In \ \frac{R_1}{ R_2}}{ {\beta}} = (\frac{1}{T_1}- \frac{1}{T_2})$

$\frac{1}{T_2} = \frac{1}{T_1} - \frac{ In \ \frac{R_1}{ R_2}}{ {\beta}}$

${T_2} = \frac{\beta T_1}{\beta - In (\frac{R_1}{R_2})T}$

Replacing our values into the above equation :

${T_2} = \frac{3650*373}{3650 - In (\frac{20000}{500})373}$

${T_2} = \frac{1361450}{3650 - 3.6888*373}$

${T_2} = \frac{1361450}{3650 - 1375.92}$

${T_2} = \frac{1361450}{2274.08}$

${T_2} = 598.68 \ K$

${T_2} = 325.68 \ ^0 \ C$

Thus, the thermistor temperature = $325.68 \ ^0 \ C$

4 0

4 years ago

Explain how the thermal energy of a swimming pool compares to the thermal energy of a lake at the same temperature.

astra-53 [7]

There is more thermal energy in the lake because there is more water which is more thermal energy

3 0

3 years ago

Grrr i don't have much time, help please T^T

mart [117]

Answer:

2. ( b ) zero

3. ( c ) 10 s

4. Uniform then decreasing

Explanation:

2.

Since the motion is uniform, initial and final velocity will be 0, hence acceleration will be zero.

3.

Initial velocity ( u ) = 5 m/s

Final velocity ( v ) = 35 m/s

Acceleration ( a ) 3 m/s^2

To find : Time ( t )

Formula : -

t = v - u / a

= 35 - 5 / 3

= 30 / 3

t = 10 s

4 0

2 years ago

Read 2 more answers

28. Ken and Musa shared a cake such that Ken got twice the size

ratelena [41]

Answer:

$Musa = \frac{1}{3}$

$Ken = \frac{2}{3}$

Explanation:

Given

$Ken = 2 * Musa$ --- Ken's share

Required

The fraction each got

Since they both shared a cake, we have:

$Ken + Musa = 1$

Substitute: $Ken = 2 * Musa$

$2 * Musa+ Musa = 1$

Factorize

$Musa(2+ 1)= 1$

$Musa(3)= 1$

Divide both sides by 3

$Musa = \frac{1}{3}$

Recall that: $Ken = 2 * Musa$

$Ken = 2 * \frac{1}{3}$

$Ken = \frac{2}{3}$

3 0

3 years ago

Speakers A and B are vibrating in phase. They are directly facing each other, are 6.69 m apart, and are each playing a 75.0-Hz t

maw [93]

Answer:

3.117 m

Explanation:

Given that:

the distance of separation between speaker A and speaker B (L) = 6.69 m

Frequency (F) = 750 -Hz tone

Velocity of speed of sound = 343 m/s

The distance from Speaker A to the first point (L₁) on the line can be calculated by using the formula:

$L_1=\frac{L-A}{2}$

where A = $\frac{Velocity ofthe sound (V)}{Frequency (F)}$

we have:

$L_1=\frac{L-\frac{V}{F} }{2}$

$L_1=\frac{6.69-\frac{343}{750} }{2}$

$L_1=\frac{6.69-0.457 }{2}$

$L_1=\frac{6.233 }{2}$

$L_1= 3.1165 m$

$L_1=3.117 m$

∴ the distance from speaker A to the first point on the line between the speakers where constructive interference occurs = 3.117 m

3 0

3 years ago