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N76 [4]
3 years ago
6

A rock is dropped from a sea cliff and hits the water 3.2s later. How high is the cliff? How long would it take sound to travel

the same distance? How long would it take light to travel this distance? Show work!
Physics
1 answer:
Kruka [31]3 years ago
4 0
<span>A rock is dropped from a sea cliff and hits the water 3.2s later. How high is the cliff?

t = sqrt(2y/g)
3.2 = sqrt(2y/9.81)
y = 50.23 m

</span><span>How long would it take sound to travel the same distance?
t = 50.23 / </span><span>343 m/s
t = 0.15 s

</span><span>How long would it take light to travel this distance? 
t = 50.23 / </span><span>299 792 458 m / s
t = 1.68x10^-7 s</span>
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A pilot is flying a commercial plane from New York City to Orlando. If the pilot fails to take the Coriolis Effect into account,
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<u>B. East of NYC</u>

Explanation:

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5 0
3 years ago
An object falls freely from rest on a planet where the acceleration due to gravity is it is on Earth. In the first 5 seconds it
weqwewe [10]

Answer:

A. The object falls a distance of 250 m

Explanation:

Hi there!

In the question, you have forgotten the acceleration due to gravity. However, looking on the web I´ve found a very similar problem in which the acceleration due to gravity was as twice as much as it is on Earth.

The equation of height of a falling object is the following:

y = y0 + v0 · t + 1/2 · g · t²

Where:

y = height of the object after a time t.

y0 = initial height.

v0 = initial velocity.

t = time.

g = acceleration due to gravity (on Earth: ≅ -10 m/s² considering the upward direction as positive).

Let´s place the origin of the system of reference at the point where the object is released so that y0 = 0. Since the object falls from rest, v0 = 0.

Then, the height of the object after 5 s will be :

y = 1/2 · 2 · g · t²    (notice that the acceleration due to gravity is 2 · g)

y = g · t²

y = -10 m/s² · (5 s)²

y = -250 m

The object falls a distance of 250 m.

8 0
3 years ago
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