Question

Find the distance CD rounded to the nearest tenth.

Answer 1

The distance between points A and B is :

$d(A,B)=4\sqrt{17} = 16.4924...$

Explanation

To find distance between points A(xA,yA) and B(xB,yB), we use formula:

$d(A, B) = \sqrt{(xB-xA)^{2}+(yB-yA)^{2}}$

In this example: xA=10 , yA=−1 , xB=−6 and yB=3 so:

$d(A, B) = \sqrt{(-6-10)^{2}+(3--1)^{2}}\\d(A, B) = \sqrt{(-16)^{2}+(4)^{2}}\\d(A, B) = \sqrt{(256+16}\\d(A, B) = \sqrt{272}\\ d(A, B) = 16.4924...$

Therefore, rounded to the nearest tenth, the answer is 16.5.