So since the vertex falls onto the axis of symmetry, we can just solve for that to get the x-coordinate of both equations. The equation for the axis of symmetry is , with b = x coefficient and a = x^2 coefficient. Our equations can be solved as such:
y = 2x^2 − 4x + 12:
y = 4x^2 + 8x + 3:
In short, the vertex x-coordinate's of y = 2x^2 − 4x + 12 is 1 while the vertex's x-coordinate of y = 4x^2 + 8x + 3 is -1.
Answer:
(1)
And we know that the lenght is y = 20.3. If we solve for x from equation (1) we got:
And replacing we got:
And the width for this case would be 15.8 in
Step-by-step explanation:
For this case we know that the photo is rectangular. Let's define:
x = the width, y= the length
And we know that the perimeter is given by:
(1)
And we know that the lenght is y = 20.3. If we solve for x from equation (1) we got:
And replacing we got:
And the width for this case would be 15.8 in
9514 1404 393
Answer:
x^2 -4x +2 = 0
Step-by-step explanation:
The other root is the conjugate of the given one, so is 2-√2. The quadratic equation in factored form is then ...
(x -2-√2)(x -2+√2) = 0
Expanding this, we get ...
(x -2)^2 -(√2)^2 = 0
x^2 -4x +4 -2 = 0
x^2 -4x +2 = 0 . . . . the equation you're looking for
