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3 years ago

What is the Validity measures of a basketball bouncing

1 answer:

3 0

This study was aimed at testing the construct validity of the basketball basic motion skills test instrument (ITK GDBB). The research used descriptive method of 3 basketball experts in the city of Cimahi; 3 experts are the expert in basketball. The instrument used was the ITB GDBB developed by Silvy (2019) consisting of top passing, bottom passing, top service, bottom service, chest passing, bounding passing, overhead passing, and leading ball (dribbling). This instrument consists of 76 items that cover 4 domains in basketball, namely chest pass, overhead pass, bound pass, and dribbling. The validity method used the construct validity of different power types. For the reliability method, it used the Kuder Ricardson (KR) and Objectivity analysis. The results of the construct validity analysis of a total of 76 items show that the score is ranged from 0.67 to 1.00. The construct validity value of 71 items in the basketball game is in the high category (= 1.00), 5 items are in the sufficient category, the relativity score is ranged from 0.75 to 0.98, and the objectivity score is ranged from 0.89 to 0.95. The conclusion is that this test instrument can be used as a standardized basic motion skill test for standardized large ball games for validity in basic motion skills in basketball games for grade VII junior high school students.

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3 years ago

Find the speed at which Superman (mass=78.0 kg) must fly into a train (mass = 17863 kg) traveling at 75.0 km/hr to stop it. Runn

lapo4ka [179]

Answer with Explanation:

We are given that

Mass of superman=m=78 kg

Mass of train=m'=17863 kg

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$1 km/h=\frac{5}{18} m/s$

Let initial speed of superman=u

Momentum=mv

Using the formula

$78u=17863\times 75$

$u=\frac{17863\times 75}{78}$

$u=17175.9 km/h$

Average horizontal force=0.58

Deceleration $a=-0.58\times 9.8=-5.68 m/s^2$

Final speed of train=v'=0

$v=u+at$

Using the formula

$0=20.8-5.68t$

$5.68t=20.8$

$t=\frac{v'-u'}{a}=\frac{0-20.8}{-5.68}$

$t=3.66 s$

$v^2-u^2=2as$

Using the formula

$0-(20.8)^2=2(-5.68)a$

$(20.8)^2=2(5.68)s$

$s={\frac{(20.8)^2}{2(5.68)}=38.1 m$

6 0

3 years ago

Read 2 more answers

Use the formula h = −16t2 + v0t. (if an answer does not exist, enter dne.) a ball is thrown straight upward at an initial speed

makkiz [27]

Using the given formula with v0=56 ft/s and h=40 ft
h = -16t2 + v0t
40 = -16t2 + 56t
16t2 - 56t + 40 = 0
Solving the quadratic equation:
t= (-b+/-(b^2-4ac)^1/2)/2a = (56+/-((-56)^2-4*16*40)^1/2)/2*16 = (56 +/- 24) / 32
We have two possible solutions
t1 = (56+24)/32 = 2.5
t2 = (56-24)/32 = 1
So initially the ball reach a height of 40 ft in 1 second.

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4 years ago

_________ is a layer of the earth that is classified not by composition

Sidana [21]

Answer:

Asthenosphere

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The asthenosphere is a part of the upper mantle just below the lithosphere that is involved in plate tectonic movement and isostatic adjustments.

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