Answer:
1.7 M
Explanation:
Given data:
Mass of AgNO₃ = 29.66 g
Volume of solution = 100 mL (100/1000 = 0.1 L)
Molarity of solution = ?
Solution;
Number of moles of AgNO₃:
Number of moles = mass/ molar mass
Number of moles = 29.66 g/ 169.87 g/mol
Number of moles = 0.17 mol
Molarity of solution:
Molarity = moles of solute / volume of solution in L
Molarity = 0.17 mol / 0.1 L
Molarity = 1.7 M
Answer:
0.25M HCl
Explanation:
The reaction of HCl with NaOH is:
HCl + NaOH ⇄ H₂O + NaCl
<em>Where 1 mole of HCl reacts per mole of NaOH</em>
The end point was reached when the student added:
0.0500L × (0.1mol / L) = 0.00500 moles of NaOH
As 1 mole of HCl reacted per mole of NaOH, moles of HCl present are:
<em>0.00500 moles HCl</em>
The volume of the sample of hydrochloric acid was 20.0mL = 0.0200L, and concentration of the sample is:
0.00500 mol HCl / 0.0200L = <em>0.25M HCl</em>
Answer:
The number of moles of the gas is 9.295 moles or 9.30 moles
Explanation:
We use PV = nRT
Where P = 4.87 atm;
V = 67.54 L
R= 0.0821Latm/molK
T = 158 C = 158 +273 K = 431 K
the number of moles can be obtained by substituting the values in the respective columns and solve for n
n = PV / RT
n = 4.87 * 67.54 / 0.0821 * 431
n = 328.9198 / 35.3851
n = 9.295moles
The number of moles is approximately 9.30moles.
Answer:
uh no I guess because your not your parents property your their child
So we end up with a total of four oxygen atoms for this calcium acetate unit and guys that truly it for this one.
