Essentially all the available nitrogen for life in the form of nitrates and ammonia would eventually disappear. Nitrogen is needed to make proteins and other chemicals so it is required for all life to exist. It gets recycled so it would take many decades in most places before the available nitrogen ran out. Many crops like beans depend on it. Humans can manufacture it but it would be hard on the ecosystems of the world and eventually probably lead to the extinction of all the ecosystems of the world.
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C. Magma from venus mantle erupted as lava.
Explanation:
A volcano is a land form which results from the eruption of molten rocks (lava) on the surface. Volcanic rocks are a special type of igneous rock that forms when molten rock cools and solidifies on the surface.
For a planet like Venus which is presently not active and little to no movement occurs within the plates, the volcanisim must have occurred when the planet was relatively young and it must have been millions of years ago.
It is widely believed that Venus was geologically active in times past. Mantle generated lava must have solidified on the surface in times past to have formed the volcano.
Evaluating other options:
Impact of space objects on Venus would lead to the formation of a crater which is a depression on the surface. The rock would be mostly metamorphic.
If water was ever present in Venus, they would have produced sedimentary rocks instead. The erosive power of water is not high enough to cut through the crust. Also, water would not aid the formation of volcanoes.
Heat is not enough to from volcanoes. Other factors are also in play.
In each mole of carbon dioxide there will be one mole of O₂.
Let us calculate the moles of carbon dioxide gas present first
The conditions are NTP it means , Temperature = 293 K and P = 1 atm
We will use ideal gas equation
PV= nRT
Where
P = Pressure of gas = 1 atm
V= 112mL=0.112L
R= gas constant =0.0821 L atm /mol K
n = moles = ?
Putting values
moles = 0.00466
Thus moles of carbon dioxide will be 0.00466
The moles of O₂ = 0.00466
Answer:
Explanation:1. NaNH2 (1-Butene)
CH3CH2CH2CH2Cl --------------> CH3CH2CH=CH2 + HCl (elimination reaction)
2. Br2, CCl4
CH3CH2CH=CH2 ---------------> CH3CH2CH(Br)CH2Br (Simple addition Reaction)
3. NaNH2 (1-Butyne)
CH3CH2CH(Br)CH2Br ----------------> CH3CH2C≡CH + 2HBr
Sodamide (NaNH2) is a very strong base and generally results in Terminal Alkynes when treated with Vicinal Dihalides.
Alcoholic KOH on the other hand results in the formation of Alkynes with triple bonds in the middle of the molecule.