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dexar [7]
3 years ago
11

​What is the wavelength of an electron that has a kinetic energy of 0.50 MeV (relativistic)?

Physics
1 answer:
NikAS [45]3 years ago
3 0

Answer:

The wavelength of electron is 6.99\times 10^{-22}\ m

Explanation:

The kinetic energy of the electron is, E=0.5\ MeV=0.5\times 10^6\ eV

We need to find the wavelength of this electron. It can be calculated using the concept of DE-broglie wavelength as :

\lambda=\dfrac{h}{\sqrt{2mE} }

h is Plank's constant

m is the mass of electron

\lambda=\dfrac{6.67\times 10^{-34}\ J-s}{\sqrt{2\times 9.1\times 10^{-31}\ kg\times 0.5\times 10^6\ eV} }        

\lambda=6.99\times 10^{-22}\ m

So, the wavelength of electron is 6.99\times 10^{-22}\ m. Hence, this is the required solution.

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A fish tank is a cube of size L × L × L, where L = 1 m, filled with water. Find
Murljashka [212]

At the bottom of the tank :

P = ρgH

P = (1000 kg/m³)(10 m/s²)(1 m)

P = 10000 N/m²

F = P • A

F = (10000 N/m²)(1 m²)

F = 10000 N

At the side of the tank :

Pav = ½ρgH

Pav = ½(1000 kg/m³)(10 m/s²)(1 m)

Pav = 5000 N/m²

F = P • A

F = (5000 N/m²)(1 m²)

F = 5000 N

3 0
2 years ago
A thin spherical glass shell in air is filled with an unknown liquid. A horizontal parallel light beam is incident on the shell
sammy [17]
I have the exact same question, any chance you figured it out since you posted this?
8 0
3 years ago
Light is incident along the normal to face AB of a glass prism of refractive index 1.54. Find αmax, the largest value the angle
marusya05 [52]

To solve this problem it is necessary to use the concepts related to Snell's law.

Snell's law establishes that reflection is subject to

n_1sin\theta_1 = n_2sin\theta_2

Where,

\theta = Angle between the normal surface at the point of contact

n = Indices of refraction for corresponding media

The total internal reflection would then be given by

n_1 sin\theta_1 = n_2sin\theta_2

(1.54) sin\theta_1 = (1.33)sin(90)

sin\theta_1 = \frac{1.33}{1.54}

\theta = sin^{-1}(\frac{1.33}{1.54})

\theta = 59.72\°

Therefore the \alpha_{max} would be equal to

\alpha = 90\°-\theta

\alpha = 90-59.72

\alpha = 30.27\°

Therefore the largest value of the angle α is 30.27°

3 0
3 years ago
This is for physical science. Can someone help me?
Radda [10]
A. 320 g
B. 160 g
C. 80 g
D. 40 g
6 0
3 years ago
Read 2 more answers
Derive this please as fast as u can​
GREYUIT [131]

Answer:

Derived in explanation

Explanation:

The law of universal gravitation was discovered by Newton in 1686. According to this law:

“Every object in this universe attracts other body with a force, which is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.”

Consider two bodies ‘A’ and ‘B’ having masses ‘m1’ and ‘m2’, respectively. They are placed with their centers at distance ‘r’ from each other.  

According to this law, force is directly proportional to the product of their masses, that is:

F\ \alpha\ (m_1)(m_2)

Also, the force is inversely proportional to the square of the distance between them, that is:

F\ \alpha\ \frac{1}{r^2}

On combining both equations we get:

Where ‘G’ is called ‘Gravitational Constant’ and its value is 6.67 x 10⁻¹¹ Nm²/kg².

6 0
3 years ago
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