Consider three resistors with unequal resistances connected in series to a battery. Which of the following statements are true?

Physics

1 answer:

Ivenika [448]4 years ago

7 0

<h2>Answer: The second Statement </h2>

<h2>The algebraic sum of the currents flowing through each of the three resistors is equal to the current through the battery. </h2><h2 />

In a series circuit, the value of the equivalent resistance $R_E$ is equal to the sum of the values of each of them:

$R_ {E}=R_{1}+R_ {2}+R_ {3}$

Where:

<h2>The equivalent resistance of the combination of resistors is greater than the resistance of any one of three resistors. </h2>

In this case the current $I$ flowing through the resistors is the same in each one. This is because the current flowing through the circuit only has one way to go, so the current intensity is the same throughout the circuit.

Therefore:

<h2>The current flowing through each of the resistors is the same and is equal to the current through the battery. </h2><h2>The algebraic sum of the voltages across the three resistors is equal to the voltage across the battery. </h2>

The battery provides a voltage $V_T$ that is the sum of the different voltages at the ends of the resistors:

$V_{T}=V_{1}+V_{2}+V_{3}$

Where the Voltage, according to Ohm's law is:

$V=R.I$

Hence, the second statement of this question is <u>True </u>

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