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SIZIF [17.4K]
3 years ago
14

Consider three resistors with unequal resistances connected in series to a battery. Which of the following statements are true?

Physics
1 answer:
Ivenika [448]3 years ago
7 0
<h2>Answer: The second Statement </h2>

<h2>The algebraic sum of the currents flowing through each of the three resistors is equal to the current through the battery.  </h2><h2 />

In a series circuit, the value of the equivalent resistance R_E is equal to the sum of the values of each of them:  

R_ {E}=R_{1}+R_ {2}+R_ {3}  

Where:  

<h2>The equivalent resistance of the combination of resistors is greater than the resistance of any one of three resistors. </h2>

In this case the current I flowing through the resistors is the same in each one. This is because the current flowing through the circuit only has one way to go, so the current intensity is the same throughout the circuit.

Therefore:  

<h2>The current flowing through each of the resistors is the same and is equal to the current through the battery.  </h2><h2>The algebraic sum of the voltages across the three resistors is equal to the voltage across the battery.  </h2>

The battery provides a voltage V_T that is the sum of the different voltages at the ends of the resistors:  

V_{T}=V_{1}+V_{2}+V_{3}  

Where the Voltage, according to Ohm's law is:  

V=R.I  

Hence, the second statement of this question is <u>True </u>

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2. Adelia holds a shiny steel spoon with its back (convex surface) facing her eyes at a distance
My name is Ann [436]

Answer:

(a) The convex mirror image, is always upright at all positions, while images formed by concave mirrors are always inverted when the object distance from the mirror is more than the mirrors focal length.

(b) An upright image is not seen for object at a distance from a concave mirror further than the focal length of the mirror, which is the spoon in the question

Therefore, the location of her eyes of approximately, 30 cm,  from the mirror is more than the mirror's focal length

Explanation:

3 0
3 years ago
The magnitude E of an electric field depends on the radial distance r according to E = A/r4, where A is a constant with unit vol
Lesechka [4]

Answer:

\Delta V = 0.053 A

Explanation:

Electric field in a given region is given by equation

E = \frac{A}{r^4}

as we know the relation between electric field and potential difference is given as

\Delta V = -\int E. dr

so here we have

\Delta V = - \int (\frac{A}{r^4}) .dr

\Delta V = \frac{A}{3r_1^3} - \frac{A}{3r_2^3}

here we know that

r_1 = 1.71 m  and r_2 = 2.89 m

so we will have

\Delta V = \frac{A}{3}(\frac{1}{1.71^3} - \frac{1}{2.89^3})

so we will have

\Delta V = 0.053 A

8 0
3 years ago
1. Which object is farthest from the origin at t=2sec
Stolb23 [73]

Answer:

that one i know only pe not that sorry again

6 0
2 years ago
A 2100-kg pile driver is used to drive a steel I-beam into the ground. The pile driver falls 5.00 m before coming into contact w
aliya0001 [1]

Answer:

   f = 878,080 N

Explanation:

mass of pile driver (m) = 2100 kg

distance of pile driver to steel beam (s) = 5 m

depth of steel driven (d) = 12 cm = 0.12 m

acceleration due to gravity (g0 = 9.8 m/s^{2}

calculate the average force exerted on the pile driver by the beam.

  • from work done = force x distance
  • work done = change in potential energy of the pile driver
  • equating the two equations above we have

               force x distance = m x g x (s - d)

              f x 0.12 = 2100 x 9.8 x (5- (-0.12))

              d = - 0.12 because the steel beam went down at we are taking its  

              initial position to be an origin point which is 0

              f = ( 2100 x 9.8 x (5- (-0.12)) ) ÷ 0.12

                   f = 878,080 N

4 0
3 years ago
A 74 kg firefighter slides, from rest, 4.9 m down a vertical pole. (a) If the firefighter holds onto the pole lightly, so that t
In-s [12.5K]

Answer:

Her speed is 9.8 meter per second

Explanation:

Newton's second law states that acceleration (a) is related with force (F) by:

\sum\overrightarrow{F}=m\overrightarrow{a} (1)

Here the only force acting on the firefighter is the weight F=mg so (1) is:

mg=ma

Solving for a:

a=g

Now with the acceleration we can use the Galileo's kinematic equation:

Vf^{2}=Vo^{2}+2a\varDelta x (2)

With Vf the final velocity, Vo the initial velocity and Δx the displacement, because the firefighter stars from rest Vo=0 so (2) is:

Vf^{2}=2a\varDelta x

Solving for Vf

Vf=\sqrt{2g\varDelta x}=\sqrt{2(9.81)(4.9)}

Vf=9.8\frac{m}{s}

6 0
3 years ago
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