Answer:
(A) 6174J, 0J.
(B) 7374J
(C) 7374J
Explanation:
See the attachment below for the calculation.
The princi6of conservation of energy has been used.
E = K1 + U1 = K2 + U2
Where E = total mechanical energy.
Taking the bottom as reference, and h =0 and as a result U2 = mg(0) = 0J.
The complete solution to the problem can be found in the attachment below.
Newtons first law of motion
object in motion stays in motion, object at rest stays at rest unless acted upon an unbalanced force
Answer:
The current is not used up. The electrons flow through the entire circuit and this travel is the current. They flow until they are not charged anymore. That is also why the circuit must be closed or else electrons would escape not just light it up for a second then go out.
Explanation:
Data:
n (Wave node)
V (Wave belly)
L (Wave length)
<span>The number of bells is equal to the number of the harmonic emitted by the string.
</span>
Wire 2 → 2º Harmonic → n = 2
Wire 1 → 1º Harmonic or Fundamental rope → n = 1
If, We have:
V = 42L
Soon:
Answer:
<span>The fundamental frequency of the string:
</span>
21 Hz
