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2 years ago

9 1/6 - 2 3/4 Please explain the steps :)

1 answer:

7 0

77/12 or 6 5/12

Explanation:

1.) Convert the mixed number to a improper fraction.

2.) You’ll get 55/6 — 11/4.

3.) Subtract the Fractions.

4.) Then you’ll get 77/22 or 6 5/12.

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Write an equation for each condition listed. The horizontal line that passes through (-7,4), The vertical line that passes throu

pashok25 [27]

Y=4 is the first one
x=-7 is the second one

5 0

2 years ago

Madison and Tanisha went out to lunch. The bill came to $18.94. Madison knows that her lunch cost 9.72. How much did Tanisha's l

Finger [1]

Answer:

Tanisha's lunch cost $9.22.

Step-by-step explanation:

Given that,

Total bill = $18.94

Cost for Madison cost = $9.72

Total cost = Tanisha's lunch + Madison's lunch

18.94 = Tanisha's lunch + 9.72

Tanisha's lunch = 18.94 - 9.72

Tanisha's lunch = 9.22

So, Tanisha's lunch cost $9.22.

4 0

2 years ago

Mindy can a drive a total of 375 miles on a full tank of gas, which is 25 gallons. Based on this information, what is the consta

stepan [7]

Answer:

Step-by-step explanation:

$\frac{25}{375} = \frac{1}{x}$

Cross multiply to get 25x = 375

Divide each side by 25 to get x = 15

5 0

1 year ago

A. Evaluate ∫20 tan 2x sec^2 2x dx using the substitution u = tan 2x.

irakobra [83]

Answer:

The integral is equal to $5\sec^2(2x)+C$ for an arbitrary constant C.

Step-by-step explanation:

a) If $u=\tan(2x)$ then $du=2\sec^2(2x)dx$ so the integral becomes $\int 20\tan(2x)\sec^2(2x)dx=\int 10\tan(2x) (2\sec^2(2x))dx=\int 10udu=\frac{u^2}{2}+C=10(\int udu)=10(\frac{u^2}{2}+C)=5\tan^2(2x)+C$ . (the constant of integration is actually 5C, but this doesn't affect the result when taking derivatives, so we still denote it by C)

b) In this case $u=\sec(2x)$ hence $du=2\tan(2x)\sec(2x)dx$ . We rewrite the integral as $\int 20\tan(2x)\sec^2(2x)dx=\int 10\sec(2x) (2\tan(2x)\sec(2x))dx=\int 10udu=5\frac{u^2}{2}+C=5\sec^2(2x)+C$ .

c) We use the trigonometric identity $\tan(2x)^2+1=\sec(2x)^2$ is part b). The value of the integral is $5\sec^2(2x)+C=5(\tan^2(2x)+1)+C=5\tan^2(2x)+5+C=5\tan^2(2x)+C$ . which coincides with part a)

Note that we just replaced 5+C by C. This is because we are asked for an indefinite integral. Each value of C defines a unique antiderivative, but we are not interested in specific values of C as this integral is the family of all antiderivatives. Part a) and b) don't coincide for specific values of C (they would if we were working with a definite integral), but they do represent the same family of functions.

3 0

2 years ago

Write in word form 64,307.009

Gnoma [55]

Answer:

sixty-four thousand three hundred seven and nine thousandths.

Step-by-step explanation:

3 0

2 years ago