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3 years ago

What mass of HCl is neutralized by 3.33 g Mg(OH)2?

1 answer:

3 0

First, you write the balanced equation for the reaction

2HCl + Mg(OH)2 ----->MgCl2 + 2H2O

Next, find the number of moles of Magnesium Hydroxide

Number of moles of Mg(OH)2 =

mass / Mr = 3.33 / 24 +2(1+16)
=0.0574 mol

Find the mole ratio between HCl and Mg(OH)2 which is 1:2

Number of moles of HCl = 0.0574 x 2 = 0.1148 mol

Mass of HCl = Mr x no. of moles
=0.1148 x (1+35.5)
=4.19 g

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Which properties represent a metal ( select all that apply )

blagie [28]

Malleable, shiny and good conductors
A B E

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3 years ago

3. A student carries out the clay-catalyzed dehydration of cyclohexanol starting with 10 moles of cyclohexanol and obtains 500 m

IrinaK [193]

Answer:

$49.45~%$

Explanation:

In this case, we have to start with the chemical reaction:

$C_6H_1_2O~->~C_6H_1_0~+~H_2O$

So, if we start with 10 mol of cyclohexanol ( $C_6H_1_2O$ ) we will obtain 10 mol of cyclohexanol ( $C_6H_1_0$ ). So, we can calculate the grams of cyclohexanol if we calculate the molar mass:

$(6*12)+(10*1)=82~g/mol$

With this value we can calculate the grams:

$10~mol~C_6H_1_0\frac{82~g~C_6H_1_0}{1~mol~C_6H_1_0}=820~g~C_6H_1_0$

Now, we have as a product 500 mL of $C_6H_1_0$ . If we use the density value (0.811 g/mL). We can calculate the grams of product:

$500~mL\frac{0.811~g}{1~mL}=405.5~g$

Finally, with these values we can calculate the yield:

$%~=~\frac{405.5}{820}x100~=~49.45%$ %= (405.5/820)*100 = 49.45 %

See figure 1

I hope it helps!

6 0

3 years ago

A hiker has packed a bag of chips as a snack. At the start of the hike the pressure was 1.5 atm and the temperature was 35*C. At

Mazyrski [523]

According to Gay-Lussac's Law the temperature and Pressure are directly proportional to each other if the amount and volume of given gas are kept constant.
Mathematically for initial and final states it is expressed as,

P₁ / T₁ = P₂ / T₂ ----- (1)
Data Given;
P₁ = 1.5 atm

T₁ = 35 °C + 273 = 308 K

P₂ = ?

T₂ = 0 °C + 273 = 273 K

Solving Eq. 1 for P₂,

P₂ = P₁ T₂ / T₁

Putting values,
P₂ = (1.5 atm × 273 K) ÷ 308 K

P₂ = 1.32 atm
Result:
As the temperature is decreased so the pressure also decreases from 1.5 atm to 1.32 atm. Therefore the bag will contract.

5 0

3 years ago

A sample of helium gas occupies a 10 cubic meter container at stp (273 k, 1 atm). what will the approximate volume become when t

Sloan [31]

He answer in here is b.7.5 cubic meters. We know this when we do the following calculation:
(10 m^3) x (1 / 1.5) x ((32 + 273) / (273)) = 7.5 m^3

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3 years ago

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