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Arte-miy333 [17]
3 years ago
13

What mass of HCl is neutralized by 3.33 g Mg(OH)2?

Chemistry
1 answer:
postnew [5]3 years ago
3 0
First, you write the balanced equation for the reaction

2HCl + Mg(OH)2 ----->MgCl2 + 2H2O


Next, find the number of moles of Magnesium Hydroxide

Number of moles of Mg(OH)2 =

mass / Mr = 3.33 / 24 +2(1+16)
=0.0574 mol

Find the mole ratio between HCl and Mg(OH)2 which is 1:2

Number of moles of HCl = 0.0574 x 2 = 0.1148 mol

Mass of HCl = Mr x no. of moles
=0.1148 x (1+35.5)
=4.19 g
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Which of the following statements holds true for a chemical change?
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Answer : The correct option is C.

Explanation :

Chemical change : It is defined as a change in which a new compounds are formed by the chemical reaction. Changes occurs in their chemical composition and properties.

The molecular structure of a substance changes in a chemical reaction is a chemical change.

  • Change in molecular structure means that there is a breaking and formation of bonds in a molecule.

The example of chemical change in terms of change in molecular structure is the reaction of hydrogen with oxygen.

The reaction of hydrogen with oxygen is,

H_2(g)+O_2(g)\rightarrow 2H_2O(l)

In this reaction, the H-H bond is break and O-H bond is form.


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The half-life of radon-222 is 3.8 days. If a sample currently contains 3.1 grams of radon-222, how much radon-222 did this sampl
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The   number  of grams of  radon 222 did it have 15.2  ago was  49.6 grams( answer  C)

 <u>calculation</u>

  • calculate the number of half life it has covered    from   15.2  days to 3.8 days

             that is  divide 15.2/ 3.8 = 4 half life

  •  half  life is time taken for a radio activity  of a specified isotope to fall to half its original mass

therefore  3.8 days ago  it was  3.1 x2 =  6.2 grams

                  7.6 days ago  it was 6.2 x2 = 12.4 grams

                   11.4  days  ago it was 12.4  x2=  24.8  grams

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5 0
3 years ago
Kerosene, a common space-heater fuel, is a mixture of hydrocarbons whose "average" formula is C₁₂H₂₆.
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The calculated enthalpy of formation of kerosene is 365.4 kJ and heat produced is 78650.3 kJ

For this, we need the normal enthalpy of formation given below

ΔH∘f(CO2)=−393.5kJ/molΔH∘f(H2O)\s=−241.8kJ/molΔH∘f(O2)=0kJ/mol

We shall now determine the enthalpy of kerosene formation:

H rxn = 24 mol H f (CO2) + 26 mol H f (H2O) + 2 mol H f (C12H26) + 37 mol H f (O2) + 1.50 104 kJ = 9444 kJ + 6286.8 kJ + 1500 kJ 2 mol H f (C12H26) = 730.8 kJ H f (C12H26) = 365.4 kJ

Kerosene has a density of 0.74 g/mL.

Kerosene volume (V) equals 0.63 gallons, or 0.63 x 3785.4, or 2384. 8 mL.

We shall now calculate the mass (m) of kerosene:

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We shall now discover the heat that 1786 generated.

Two grams of kerosene

Kerosene's molar mass is 170.33 g/mol.

The mass of two moles of kerosene is equal to 2*170.33*340.66g.

1.50104kJ of heat are generated by 340.66 g of kerosene.

1786 produced heat.

Kerosene 2 grams = 1.50 104 kJ 340.66 1786.2 g = 78650.3 kJ

Learn more about enthalpy here-

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What characterizes a Homo genesis mixture
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Answer:

The correct answer would be the third choice.

Homo-genesis mixtures are the same in composure, and will be hard to break apart other then with chemical means.

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