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3 years ago

Answer the question in image attached Thanks!

Chemistry

2 answers:

arsen [322]3 years ago

6 0

Answer: i think the 3,4,2

Explanation:

Alisiya [41]3 years ago

3 0

Answer:

i think its 2, 3 and 4

ionic and molecular compounds, polyatomic ions, ch chemical equations

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Elements in the same column down belong to the same.......

vladimir2022 [97]

I think the answer is the number of electrons. Hope it help :)

8 0

4 years ago

The equation represents the decomposition of a generic diatomic element in its standard state. 12X2(g)⟶X(g) Assume that the stan

aliina [53]

Answer:

$K^{2000K}=0.774\\\\K^{3000K}=12.56$

Explanation:

Hello,

In this case, considering the reaction, we can compute the Gibbs free energy of reaction at each temperature, taking into account that the Gibbs free energy for the diatomic element is 0 kJ/mol:

$\Delta _rG=\Delta _fG_{X}-\frac{1}{2} \Delta _fG_{X_2}=\Delta _fG_{X}$

Thus, at 2000 K:

$\Delta _rG=\Delta _fG_{X}^{2000K}=4.25kJ/mol$

And at 3000 K:

$\Delta _rG=\Delta _fG_{X}^{3000K}=-63.12kJ/mol$

Next, since the relationship between the equilibrium constant and the Gibbs free energy of reaction is:

$K=exp(-\frac{\Delta _rG}{RT} )$

Thus, at each temperature we obtain:

$K^{2000K}=exp(-\frac{4250J/mol}{8.314\frac{J}{mol\times K}*2000K} )=0.774\\\\K^{3000K}=exp(-\frac{-63120J/mol}{8.314\frac{J}{mol\times K}*3000K} )=12.56$

In such a way, we can also conclude that at 2000 K reaction is unfavorable (K<1) and at 3000 K reaction is favorable (K>1).

Best regards.

4 0

3 years ago

An atom can absorb any amount of energy to become excited. True False

lora16 [44]

The correct answer would be false

Hope this helped! ☺

6 0

3 years ago

Green plants absorb sunlight to power photosynthesis, the chemical synthesis of food from water and carbon dioxide. The compound

tekilochka [14]

Answer: The frequency of this light is $6.74\times 10^{17}Hz$ .

Explanation:-

To calculate the frequency of light, we use the equation:

$\lambda=\frac{c}{\nu}$

where,

$\lambda$ = wavelength of the light = $430nm=430\times 10^{-9}m$ $1nm=10^{-9}m$

c = speed of light = $2.9\times 10^8m/s$

$\nu$ = frequency of light = ?

$\nu=\frac{c}{\lambda}$

$\nu=\frac{2.9\times 10^8m/s}{430\times 10^{-9}m}$

$\nu=\frac{2.9\times 10^8m/s}{430\times 10^{-9}m}=6.74\times 10^{17}s^{-1}=6.74\times 10^{17}Hz$

The frequency of this light is $6.74\times 10^{17}Hz$ .

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4 years ago

What would be considered as a homogeneous among the the following mixtures?

krek1111 [17]

Answer:soda

Explanation:A homogeneous mixture is a mixture in which individual components of the mixture cannot be identified and since individual components of soda cannot be identified it is a homogeneous mixture

8 0

1 year ago