To solve the exercise it is necessary to apply the equations necessary to apply Newton's second law and the concept related to frictional force.
An angle of 30 degrees is formed on the vertical at an applied force of 2.3N
In this way the frictional force, opposite to the movement will be given by
where,
Kinetic friction constant
N = Normal Force (Mass*gravity)
The friction force is completely vertical and opposes the rising force of 2.3 N. The Normal force acts perpendicular to the surface (vertical) therefore corresponds to the horizontal component of the applied force.
The ascending force would be given by
As the block is moving upward, the friction force acts downward, also its weight acts downward. We can have
Considering the horizontal force the normal force on the block must be balanced by the horizontal component of pishing foce
Then the frictional force
Therefore the coefficient of kinetic friction is 0.26
Other families might be more private, so a girl might not know exactly what to say or whom to tell. But this news needs to be shared, at least with one grown-up in the family. You might just pull the person aside and say it clearly, like this: "I got my first period today. Do you think you can help me get some supplies?"
Answer:
Refraction splits the light into its component wavelengths, and you see a rainbow.
Answer:
Answer B is the correct answer: "<em>Motion of one projectile as seen from the other is a straight line.</em>"
Explanation:
Let's write the equations of motion for each projectile, using that projectile 
is launched with velocity which has components associated with the angle of launching, given in x and y coordinates as: 
.
Similarly, assume that projectile b is launched with velocity 
with components due to the launching angle = 
then the equations of motion for the two projectiles launched at the same time (t) from the same spot (position that we assume to be at the origin of coordinates to simplify formulas) are:
therefore, from the frame of reference of projectile "b", the x and y position of projectile "" would be:
which is linear in "t"
![y_{a\,\,b}=y_a-y_b= a_y\,t-\frac{1}{2} g\,t^2-\left[ b_y\,t-\frac{1}{2} g\,t^2\right]=(a_y-b_y)\,t](https://tex.z-dn.net/?f=y_%7Ba%5C%2C%5C%2Cb%7D%3Dy_a-y_b%3D%20a_y%5C%2Ct-%5Cfrac%7B1%7D%7B2%7D%20g%5C%2Ct%5E2-%5Cleft%5B%20b_y%5C%2Ct-%5Cfrac%7B1%7D%7B2%7D%20g%5C%2Ct%5E2%5Cright%5D%3D%28a_y-b_y%29%5C%2Ct)
which is also linear in t.
Therefore the motion of one projectile with reference to the other is a straight line (answer B)
Notice as well that this two projectiles cannot collide because they have been launched together, and supposedly at different speeds and angles. The only way that they can share the same x-coordinate and the same y-coordinate at the same time "t" is if their velocity components are equal, which is not what we are told.
Regular electrical needs such as heat, a/c, appliances, anything that would be used regularly with electricity. Most electrical companies use gas, coal, and other nonrenewable resources to power houses. Solar power is just a renewable way of gathering power from the sun and converting it to electricity.
