Question

AYUDAAAAAAA Un ciclista de montaña se mueve cuesta abajo por la pendiente, si acelera a 3 m/s2 y se demora en bajar 15 minutos (900 segundos) ¿Qué distancia recorre? AYUDENME PORFAVOOOR

Answer 1

The question is: HELPAAAAAAA A mountain biker moves downhill if he accelerates at 3 m / s2 and takes 15 minutes (900 seconds) down, how far does he travel? HELP ME PLEASE

Answer: The distance travelled by the mountain biker is 2430 km.

Explanation:

Given: Acceleration = $3 m/s^{2}$

Time = 15 minutes (900 sec)

Displacement = ?

Formula used to calculate the final velocity is as follows.

$v = u + at$

where,

v = final velocity

u = initial velocity = 0 m/s (here)

t = time

a = acceleration

Substitute the values into above formula as follows.

$v = u + a \times t\\v = 0 + 3 m/s^{2} \times 900 s\\= 2700 m/s$

The relation between velocity (speed) and distance is as follows.

$Speed = \frac{Distance}{time}\\2700 m/s = \frac{Distance}{900 s}\\Distance = 2430000 m (1 m = 0.001)\\= 2430 km$

Thus, we can conclude that distance travelled by the mountain biker is 2430 km.