AYUDAAAAAAA Un ciclista de montaña se mueve cuesta abajo por la pendiente, si acelera a 3 m/s2 y se demora en bajar 15 minutos (
1 answer:
The question is: HELPAAAAAAA A mountain biker moves downhill if he accelerates at 3 m / s2 and takes 15 minutes (900 seconds) down, how far does he travel? HELP ME PLEASE
Answer: The distance travelled by the mountain biker is 2430 km.
Explanation:
Given: Acceleration =
Time = 15 minutes (900 sec)
Displacement = ?
Formula used to calculate the final velocity is as follows.
where,
v = final velocity
u = initial velocity = 0 m/s (here)
t = time
a = acceleration
Substitute the values into above formula as follows.
The relation between velocity (speed) and distance is as follows.
Thus, we can conclude that distance travelled by the mountain biker is 2430 km.
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Answer:
refer to the above attachment
Answer:
Length of third side = 3.97m
Explanation:
First of all, let we draw the triangle from the given information assuming our first corner is A. second corner is B and third corner is C.
From A-B we have distance = 5.5m = Say it c
From B-C we have distance = 4.3m = Say it a
From A-C we have distance = ? = Say it b which we have to find out.
Using the Law of Cosines: The square of the unknown side equals to the sum of squares of other 2 sides and subtracting 2*(Product of other sides)*(Cos(Angle opposite to the unknown side)
For our case it is:
b² = a² + c² - 2acCos(B) - Say it equation 1
From the attached triangle you may see that, a & c are our known sides and B is the angle opposite to the side b.
There values are:
a = 4.3m; c = 5.5m ; Angle B = 0.8 rad = 0.8 * 57.3 = 45.84 degrees where 1 rad = 57.3 degrees
Now by putting the respectve values in equation 1 we have:
b² = (4.3)² + (5.5)² - 2*4.3*5.5*Cos(45.84)
b² = 18.49 + 30.25 - 32.95
b² = 15.79
b = √15.79
b = 3.97m
Thus the length of third side is 3.97m.
PS: The picture of triangle is being attached for yours understanding.
