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Irina-Kira [14]
3 years ago
5

3. Which expression completes the table

Mathematics
1 answer:
koban [17]3 years ago
7 0
The table represents the relationship between the number of days, x, and the number of patients in a hospital showing flu symptoms.
100
18
13
Which statement is true?
The number of patients showing flu symptoms decreases at a constant rate as the number of days increases.
The number of patients showing flu symptoms decreases as the number of days increases but not at a constant rate.
The number of patients showing flu symptoms increases at a constant rate as the number of days increases.
The number of patients showing flu symptoms increases as the number of days increases but not at a constant rate.
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We learned in that about 69.7% of 18-20 year olds consumed alcoholic beverages in 2008. We now consider a random sample of fifty
maw [93]

Answer:

(1) The expected number of people who would have consumed alcoholic beverages is 34.9.

(2) The standard deviation of people who would have consumed alcoholic beverages is 10.56.

(3) It is surprising that there were 45 or more people who have consumed alcoholic beverages.

Step-by-step explanation:

Let <em>X</em> = number of adults between 18 to 20 years consumed alcoholic beverages in 2008.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.697.

A random sample of <em>n</em> = 50 adults in the age group 18 - 20 years is selected.

An adult, in the age group 18 - 20 years, consuming alcohol is independent of the others.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 50 and <em>p</em> = 0.697.

The probability mass function of a Binomial random variable <em>X</em> is:

P(X=x)={50\choose x}0.697^{x}(1-0.697)^{50-x};\ x=0,1,2,3...

(1)

Compute the expected value of <em>X</em> as follows:

E(X)=np\\=50\times 0.697\\=34.85\\\approx34.9

Thus, the expected number of people who would have consumed alcoholic beverages is 34.9.

(2)

Compute the standard deviation of <em>X</em> as follows:

SD(X)=\sqrt{np(1-p)}=\sqrt{50\times 0.697\times (1-0.697)}=10.55955\approx10.56

Thus, the standard deviation of people who would have consumed alcoholic beverages is 10.56.

(3)

Compute the probability of <em>X</em> ≥ 45 as follows:

P (<em>X</em> ≥ 45) = P (X = 45) + P (X = 46) + ... + P (X = 50)

                =\sum\limits^{50}_{x=45} {50\choose x}0.697^{x}(1-0.697)^{50-x}\\=0.0005+0.0001+0.00002+0.000003+0+0\\=0.000623\\\approx0.0006

The probability that 45 or more have consumed alcoholic beverages is 0.0006.

An unusual or surprising event is an event that has a very low probability of success, i.e. <em>p</em> < 0.05.

The probability of 45 or more have consumed alcoholic beverages is 0.0006. This probability value is very small.

Thus, it is surprising that there were 45 or more people who have consumed alcoholic beverages.

6 0
3 years ago
How do I simplify this?
Kipish [7]
(x+2) is the answer.
you distribute (x+2)^2 then cancel out 'likes', which leaves you with (x+2)
3 0
4 years ago
Finally, find the y-value for x=0.96 by substituting x=0.96 in the original equation and solving for y using a computer or calcu
Sati [7]
To answer this, we need the original equation.
4 0
3 years ago
Simplify. <br> √3(√6+√15)<br><br> a. √32+9√5<br> b. 3√7<br> c. 3√2+3√5<br> d. 2√3+3√5
Vesna [10]

Answer:

c

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Pentru a culege nectar 45 de albine au vizitat, intr-o singura exeditie, unele 60 flori, iar altele 75 de flori . Stiing=d ca au
labwork [276]
69.3 I think hope that helps
7 0
3 years ago
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