Question

Potassium chlorate decomposes to produce potassium chloride and oxygen gas according to the balanced equation below. If 1.00 g of potassium chlorate decomposes, and 0.500 g of solid potassium chloride is collected, what is the theoretical yield of potassium chloride and the % Yield of potassium chloride

Answer 1

Answer: The theoretical yield of potassium chloride is 0.596 grams and the % Yield of potassium chloride is 83.9%

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$    

$\text{Moles of} KClO_3=\frac{1.00g}{122.5g/mol}=0.008moles$  

$2KClO_3\rightarrow 2KCl+3O_2$  

According to stoichiometry :

2 moles of $KClO_3$ produce= 2 moles of $KCl$

Thus 0.008 moles of $KClO_3$ will produce=$\frac{2}{2}\times 0.008=0.008moles$  of $KCl$

Theoretical yield of $KCl=moles\times {\text {Molar mass}}=0.008moles\times 74.5g/mol=0.596g$

% yield = $\frac{\text {Actual yield}}{\text {Theoretical yield}}\times 100=\frac{0.500g}{0.596g}\times 100\%=83.9\%$

The theoretical yield of potassium chloride is 0.596 grams and the % Yield of potassium chloride is 83.9%