How many electrons are necessary to produce a charge of "-0.80" C

Chemistry

1 answer:

docker41 [41]2 years ago

6 0

Answer:

5.0x10^18

Explanation:

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Assume that the test tube shown started out having 10.00 g of mercury(II) oxide. After heating the test tube briefly, you find 1

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This problem is providing information about the initial mass of mercury (II) oxide (10.00 g) which is able to produce liquid mercury (8.00 g) and gaseous oxygen and asks for the resulting mass of the latter, which turns out to be 0.65 g after doing the corresponding calculations.

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