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Vsevolod [243]
3 years ago
9

Of the reactions below, only ________ is not spontaneous. Mg (s) 2HCl (aq) MgCl2 (aq) H2(g) 2Ag (s) 2HNO3 (aq) 2AgNO3 (aq) H2 (g

) 2Ni (s) H2SO4 (aq) Ni2SO4 (aq) H2 (g) 2Al (s) 6HBr (aq) 2AlBr3 (aq) 3H2 (g) Zn (s) 2HI (aq) ZnI2(aq) H2 (g)
Chemistry
2 answers:
Dvinal [7]3 years ago
8 0

Answer:

The answer to the question is

2Ag (s) +2HNO₃ (aq) →2AgNO₃ (aq)+ H₂ (g)

Explanation:

The position of a cell on the reduction potential table determines if a reduction reaction will be spontaneous

The higher the positive reduction potential  the higher the spontaneity of the reduction reaction. that is if the E⁰ cell is positive the cell is a spontaneous voltaic cell, however if the E⁰ cell is negative the cell is a electrolytic non-spontaneous cell

On the standard potential table silver has a low positive potential of

Ag⁺ + e⁻ → Ag = 0.799

It is an oxidizing agent tending to scarcely release electrons, therefore for the reaction to take place, there has to be some external supply of electromotive force.

madreJ [45]3 years ago
4 0

Answer:

2Ag (s) + 2HNO₃ (aq)  2AgNO₃ (aq) + H₂ (g)

Explanation:

2Ag (s) + 2HNO₃ (aq)  2AgNO₃ (aq) + H₂ (g)

Ag is below H₂ in reactivity series. Therefore Ag does not spontaneously replace H₂ from any compound.

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Hydrogen gas and fluorine gas will react to form hydrogen fluoride gas. What is the standard free energy change for this reactio
Marta_Voda [28]

Answer:

\Delta G=-541.4kJ/mol

Explanation:

Hello there!

In this case, according to the given information, it turns out firstly necessary to write out the described chemical reaction as shown below:

H_2+F_2\rightarrow 2HF

Now, we set up the expression for the calculation of the standard free energy change, considering the free energy of formation of each species, specially those of H2 and F2 which are both 0 because they are pure elements:

\Delta G=2\Delta G_f^{HF}-(\Delta G_f^{H_2}+\Delta G_f^{F_2})\\\\\Delta G=2*-270.70kJ/mol-(0kJ/mol+0kJ/mol)\\\\\Delta G=-541.4kJ/mol

Regards!

4 0
2 years ago
Objects that are able to fall have what type of energy?
ASHA 777 [7]

Answer:

kinetic energy

Explanation:

because of the movement of gravity and space

4 0
3 years ago
The addition of an inert gas has no effect on the equilibrium position of a gaseous reaction because ______. Multiple choice que
boyakko [2]

Inert gas does not affect the equilibrium position:

It is because the partial pressures of the reaction components remain the same.

What is Inert Gas?

  • Under a given set of conditions, an inert gas is a gas that does not undergo chemical reactions.
  • The noble gases (helium, neon, argon, krypton, xenon, and radon) were previously known as "inert gases" due to their perceived lack of involvement in any biochemical processes.
  • Because inert gases are non-reactive, they do not affect equilibrium partial pressures and thus do not affect volume.
  • An inert gas does not react with the reactants or products; it does not change the concentration of the products and reactants. Furthermore, because the volume is constant, the concentrations are unaffected. As a result, this does not affect equilibrium.

The equilibrium position won't change if an inert gas is added. A volume change won't change the equilibrium position if the total moles of gas in the products and reactants are the same. When the volume is reduced, the process changes to create fewer moles of gas.

Learn more about the inert gas here,

brainly.com/question/15909389

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5 0
2 years ago
How does the amount of salt dissolve in water affect the density of water
ad-work [718]

Answer:

Adding salt to the water increases the density of the solution because the salt increases the mass without changing the volume very much. When you add table salt (sodium chloride, NaCl) to water, the salt dissolves into ions, Na+ and Cl-. The volume increases by a small factor, but the mass increases by a bigger factor.

Explanation:

3 0
3 years ago
What is the freezing point of an aqueous 1.58 molal nacl solution?
Alina [70]
<span>Tf is the freezing point of the solution(the solvent plus solute). T*f is the freezing point of the pure solvent(without solute) i is the van't Hoff factor.It is approximately the number of particles in solution that are made for each particle of the solute that is placed into solution.Therefore, for nonelectrolytes, i = 1. Kf is the freezing point depression constant.For water, Kf = 1.86 Degree C/m, or 1.86 Degree C.kg/mol. Tf is -1.58 Degree C</span>
4 0
3 years ago
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