Write a polynomial to represent the perimeter of a rectangle with sides 2x+1 and 3x

Please help me :'( 25 points!

likoan [24]

Answer:

$15,339

Step-by-step explanation:

C(x) = 0.5x² − 100x + 20,339

Since this is a parabola, the minimum cost is at the vertex:

x = -b / (2a)

x = -(-100) / (2 × 0.5)

x = 100

So the minimum cost is:

C(100) = 0.5(100)² − 100(100) + 20,339

C(100) = 15,339

6 0

3 years ago

Please answer quickly and with the write answer.

r-ruslan [8.4K]

(2/5)(1/4) = 2/20 = 1/10

Choice A.

3 0

3 years ago

What's the formula to find GP?

frosja888 [35]

Answer:

The general form of a GP is a, ar, ar2, ar3 and so on. The nth term of a GP series is Tn = arn-1, where a = first term and r = common ratio = Tn/Tn-1) . The sum of infinite terms of a GP series S∞= a/(1-r) where 0< r<1. If a is the first term, r is the common ratio of a finite G.P.

hope helps

6 0

4 years ago

Read 2 more answers

1. A company has a cash portfolio measured in millions. The drift is 0.1 per month, variance is 0.16per month. The initial cash

Romashka-Z-Leto [24]

Answer:

Step-by-step explanation:

From the information given:

The probability distribution at the end of 6 months is determined as follows:

After 6 months;

Mean of probability distribution = value of Initial cash + $\alpha$ T

=2.0 +(0.1 × 6)

=2.6

After 6 months;

The probability distribution's standard deviation is estimated by using the following formula:

Standard deviation:

$= b\sqrt{T}$

$= 0.4 \times \sqrt{6}$

= 0.9798

Hence, after 6 months;

The company's cash position is supposed to be allocated monthly, with the following expenses.

Mean 2.6

Standard deviation 0.9798

Variance 0.96

After 12 months, the probability distribution is as follows:

Mean = value of Initial cash + $\alpha$ T

= 2.0 +(0.1 × 12)

= 3.2

The standard deviation is:

The standard deviation of probability distribution = $b \sqrt{T}$

$= 0.4 \times \sqrt{12}$

= 1.3856

Hence, after 6 months;

The company's cash position is supposed to be allocated monthly, with the following expenses.

Mean 3.2

Sandard deviation 1.3856

Variance 1.92

b)

in 6-month distribution, the probability of the negative value of the cash position is as follows.

Now, for us to find the negative cash distribution;

We need to estimate the z -scores value.

The z-score inform us greatly on the concept of how far a particular data point is from the mean.

For a normal distribution;

$z = \dfrac{x-\mu}{\sigma}$

Here;

the value of x = zero as a result that if it exceeds zero. the cash position will be negative.

∴

$z = \dfrac{x-\mu}{\sigma}$

$z = \dfrac{0 - 2.6}{0.9798}$

$z = -2.6536$

Using the standard distribution tables, it is now possible to calculate that the likelihood N(-2.65) equals 0.004 or 0.4 percent.

As a result, there's a 0.4 percent chance of getting a negative cash balance after six months.

For 12 months distribution:

The Probability of negative cash position is calculated as follows:

$z = \dfrac{x-\mu}{\sigma} \\ \\ z = \dfrac{0-3.2}{1.3856} \\ \\ z = -2.3094$

Using the standard distribution tables,

N(-2.31) equals 0.0104 or 1.04 percent.

As a result, there's a 1.04 percent chance of getting a negative cash balance after 1 year

c) To determine the time period over which the likelihood of achieving a negative cash condition is highest, it's necessary to examine the z-score more closely. Essentially, the z-score measures the difference between a given value(x) and the mean of all potential values $(\mu)$ , expressed in terms of the total set's standard deviation $(\sigma)$

This suggests that the higher the z-score, the greater the difference occurring between x and $\mu$ , and thus the likelihood of receiving x is minimal. As a result, the best chance of finding a certain value is when the z-score is the lowest.

To do so, calculate the derivative of the z-score in relation to the time interval. The point where the derivative is equivalent to zero is where the z-scores are at their lowest.

The first step is to go over the z-score formula in more detail, as seen below.;

$z = \dfrac{x-\mu}{\sigma} \\ \\ z = \dfrac{0-(initial \ value + \alpha T)}{b \sqrt{T}} \\ \\ z = \dfrac{-initial \ value }{b\sqrt{T}}-\dfrac{a \sqrt{T}}{b} \\ \\$

Now, compute the derivative of this equation with respect to T as follows:

$\dfrac{dz}{dT}= \dfrac{initial \ value \times T^{-\dfrac{3}{2}}}{2b} - \dfrac{aT^{-\dfrac{1}{2}}}{2b}$

Now, figure out the value of T at which this derivative is equal to zero by substituting all values as follows:

$0 = \dfrac{2.0 \times T^{-\dfrac{3}{2}}}{2\times 0.4}- \dfrac{0.1 \times T^{-\dfrac{1}{2}}}{2 \times 0.4} \\ \\ \\ 0.1 \times T^{-\dfrac{1}{2}}= 2.0 \times T^{-\dfrac{3}{2}} \\ \\ \\T = \dfrac{2}{0.1} \\ \\ \\ T = 20$

As a result, the time period in which achieving a negative cash condition is = 20 months.

3 0

3 years ago

A rectangular plot 72 metres long and 20 metres wide on a school farm sided into 18 equal plots. What the area of each plot?

marin [14]

Answer:

Step-by-step explanation:

There are many ways this could be done, but the simplest way is to divide 18 into 72. That gives 4. So each plot is 4 * 20 = 80 m^2

If you are willing to use fractions, the answer could be 20*72 / 18 = 8 * 10 which is more feasible and still gives 80, but the land may not permit it. However math will.

It's hard to give an exact answer when it is this open ended.

6 0

3 years ago