Answer: Both cannonballs will hit the ground at the same time.
Explanation:
Suppose that a given object is on the air. The only force acting on the object (if we ignore air friction and such) will be the gravitational force.
then the acceleration equation is only on the vertical axis, and can be written as:
a(t) = -(9.8 m/s^2)
Now, to get the vertical velocity equation, we need to integrate over time.
v(t) = -(9.8 m/s^2)*t + v0
Where v0 is the initial velocity of the object in the vertical axis.
if the object is dropped (or it only has initial velocity on the horizontal axis) then v0 = 0m/s
and:
v(t) = -(9.8 m/s^2)*t
Now, if two objects are initially at the same height (both cannonballs start 1 m above the ground)
And both objects have the same vertical velocity, we can conclude that both objects will hit the ground at the same time.
You can notice that the fact that one ball is fired horizontally and the other is only dropped does not affect this, because we only analyze the vertical problem, not the horizontal one. (This is something useful to remember, we can separate the vertical and horizontal movement in these type of problems)
92 grams of Y would combine with 46 grams of X
Kinetic Energy is calculated by KE= 1/2mv2
I believe it is speed.
Hope this helps!
Answer:
6.88 m/s
Explanation:
The Conservation of Energy states that:
Initial Kinetic Energy + Initial Potential Energy = Final Kinetic Energy + Final Potential Energy
So we can write
We can cancel the common factor of 
which leaves us with
Lets solve for 
Subtract 
from both sides of the equation.
Multiply both sides of the equation by 2.
Simplify the left side.
Apply the distributive property.
Cancel the common factor of 2.
Take the square root of both sides of the equation to eliminate the exponent on the right side.
We are given 
.
We can now solve for the final velocity.
Anything multiplied by 0 is 0.
