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Shtirlitz [24]
4 years ago
12

An ac generator with Em = 223 V and operating at 399 Hz causes oscillations in a series RLC circuit having R = 222 Ω, L = 147 mH

, and C = 23.1 μF. Find (a) the capacitive reactance XC, (b) the impedance Z, and (c) the current.
Physics
1 answer:
Doss [256]4 years ago
3 0

Answer:

Xc= 17.267 Ω,   Z= 415.5 Ω,   I= 0.537 A

Explanation:

Em = 223 V

f= 300 Hz, R = 222 Ω, L = 147 mH,  C = 23.1 μF

a)

Capacitive reactance = Xc=?

Xc= \frac{1}{2\pi fC}

Xc=1/2pi *399*23.1*10^-6

Xc= 17.267 Ω

b).

Z=\sqrt{ R^2 + (Xl - Xc)^2}

Xl= 2π * f * L  

Xl= 2π * 399 * 147 * 10^{-3}

Xl= 368.5 Ω

Z=\sqrt{ R^2 + (Xl - Xc)^2} = \sqrt{222^2 + (368.5 - 17.267)^2}

Z= 415.5 Ω  

c).

Current:

I= V / Z= Em / Z

I= 223/415.5

I= 0.537 A

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<h3>What is the straight forward meaning of acceleration?</h3>

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According to therefore mentioned statement,

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A mass is attached to an ideal spring. At time t = 0 the spring is at its natural length and the mass is given an initial veloci
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t = T/4

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U = \frac{1}{2}kx^2

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So the first time the mass reaches to its amplitude can be found by the following equation of motion:

x = A\cos(\omega t + \phi)\\\phi = \pi/2 ~because ~at ~t= 0, ~ x = 0\\0 = A\cos(0 + \pi/2)\\x = A\cos(\omega t + \pi/2)

When the mass reaches the amplitude:

A = A\cos(\omega t + \pi/2)\\1 = \cos(\omega t + \pi/2)\\\omega t + \pi/2 = \pi

because cos(π) = 1.

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Using ω = 2π/T,

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An incident light ray hits a plane surface at 20 degrees (hint: remember where the angle is measured from). What is the angle be
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