Answer:

Explanation:
The work of force 2 will be given by the vectorial equation
. We know the value of
and have information about its movement, which relates to the net force
.
About this movement we can obtain the acceleration using the equation
. Since it departs from rest we have
.
And then using Newton's 2dn Law we can obtain the net force F=ma, thus we will have 
And we had the work done by force 2 as:

(The sign will be given algebraically since we take positive the direction to the right.)
With our values:

<em>Another (shorter but maybe less intuitive way for someone who is learning) way of doing this would have been to say that the work done by both forces would be equal to the variation of kinetic energy:</em>
<em>
</em>
<em>Which leads us to the previous equation straightforwardly.</em>
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Answer:
1100Joules
Explanation:
Workdone = force x distance
Force= 500N
Distance = 2.2m
So, workdone = 500 x 2.2
= 1100Joules
Answer:
<h2>solusion </h2><h2>
Explanation:</h2><h2>the answer in 984 </h2>
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Answer:
6 m/s
Explanation:
Given that :
mass of the block m = 200.0 g = 200 × 10⁻³ kg
the horizontal spring constant k = 4500.0 N/m
position of the block (distance x) = 4.00 cm = 0.04 m
To determine the speed the block will be traveling when it leaves the spring; we applying the work done on the spring as it is stretched (or compressed) with the kinetic energy.
i.e 





v = 6 m/s
Hence,the speed the block will be traveling when it leaves the spring is 6 m/s