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quester [9]
4 years ago
14

How does energy and temperature affect the density of fluids (liquids and gases)?​

Physics
1 answer:
Alex Ar [27]4 years ago
3 0

Answer: When a liquid or gas is heated, the molecules move faster, bump into each other, and spread apart. Because the molecules are spread apart, they take up more space. ... The molecules move more slowly and take up less space. Therefore temperature can affect density.

Explanation:

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A car travels 60 miles in the first 2 hours and 68 miles in the next 2 hours
Gemiola [76]

32miles/hr

Explanation:

Given parameters:

Distance 1 = 60miles

Time 1 = 2hrs

Distance 2 = 68miles

Time 2 = 2hrs

Unknown:

Average speed of the car =  ?

Solution:

Average speed is the total distance covered in a particular duration of time.

   Average speed = \frac{total distance}{total time taken}

 Total time taken = time 1 + time 2 = 2hrs + 2hrs = 4hrs

  Total distance = distance 1 + distance 2 = 60miles + 68miles = 128miles

Average speed = \frac{128miles}{4hrs} = 32miles/hr

learn more:

Motion brainly.com/question/2863017

#learnwithBrainly

6 0
4 years ago
A 3.80-m-long, 500 kg steel beam extends horizontally from the point where it has been bolted to the framework of a new building
Virty [35]

Answer:

Explanation:

The question is ;

3.80 m-long, 500. kg steel beam extends horizontally from the point

where it has been bolted to the framework of a new building under

construction. A 67.0 kg construction worker stands at the far end of

the beam. What is the magnitude of the torque about the point where the beam is bolted into place?

Solution:

Here two torques are in action

a) torque T1 due to weight of worker at the edge of the beam - at center of the beam

b) torque T2 due to weight of the uniform beam - at the point where the beam is bolted

So we first calculate the torque produced due to weight of the worker;

We can see that;

Distance of worker from the center of the beam = 1.9m

Mass of the worker = 67 kg

Value of g= 9.8 m/sec2

T1=force × distance from point of rotation

Here force is weight of the worker which is = mass × g=67×9.8=656.6 N

So the torque is

T1= 656.6×1.9=12225.892 Nm

or

T1 = 12225.892 Nm

Now torque by the beam itself ;

Length of the beam from its center point to the bolt point = 1.9 m

Weight force of beam acting at center point= mass× g= 500×9.8=4900 N

Torque T2 at bolt point by the beam weight = weight of beam × length of beam from its center to the bolt point = 4900×1.9=9310 Nm

T2=9310Nm

So total torque = T1+T2= 12225.892+9310=21565.892 Nm

8 0
3 years ago
What is the volume of an object that has a mass of 675 g and a density of 15 g/cm3 ?
SpyIntel [72]

Answer:

45

Explanation:

because you divide volume and mass

8 0
3 years ago
Consider a particle moving along the x-axis where x(t) is the position of the particle at time t, x'(t) is its velocity, and x''
Lady_Fox [76]

Answer:

We know that the acceleration of the particle is defined as

a(t)=\frac{dv}{dt}

Since it is given that

v(t)=\frac{5}{\sqrt{t}}\\\\\therefore a(t)=\frac{d(\frac{5}{\sqrt{t}})}{dt}\\\\a(t)=5\times \frac{dt^{-\frac{1}{2}}}{dt}\\\\=\frac{-5}{2}t^{\frac{-1}{2}-1}\\\\\therefore a(t)=x''(t)=\frac{-2.5}{t^{\frac{3}{2}}}

Now by definition of velocity we have

v(t)=\frac{dx(t)}{dt}\\\\\Rightarrow dx(t)=v(t)dt

Integrating on both sides we get

v(t)=\frac{dx(t)}{dt}\\\\\int dx(t)=\int v(t)dt\\\\x(t)=\int v(t)dt

Applying values we get

v(t)=\frac{dx(t)}{dt}\\\\\int dx(t)=\int v(t)dt\\\\x(t)=\int \frac{5}{t^{\frac{1}{2}}}dt\\\\\therefore x(t)=\frac{5}{0.5}\int t^{-0.5}dt\\\\x(t)=10\sqrt{t}+c

To find the constant we note that at t=1 the particle is at x=12 Thus applying values in the above equation we get

c=12-10\\\therefore c=2\\\\x(t)=10\sqrt{t}+2

6 0
3 years ago
Owen is going on a multi-day hike up a large mountain. He wants to know what clothes he should bring for the higher elevation as
faltersainse [42]
The answer is c hope this helps
8 0
3 years ago
Read 2 more answers
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