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Margaret [11]
3 years ago
11

A __ is used to measure air pressure.

Physics
2 answers:
larisa86 [58]3 years ago
8 0
A barometer is used to measure air pressure!
PSYCHO15rus [73]3 years ago
3 0

Answer:

Barometer is used to measure air pressure.

Explanation:

Barometer :

Barometer used to measure the air pressure.

It is the scientific device which is used to measure the atmospheric pressure.

Atmospheric pressure change with the distance above and below the sea level.

When the air pressure is greater, then the mercury rises the higher.

Air pressure :

The weight of the air molecules pressing down on the earth it is called air pressure.

The density of air molecules is higher at sea level where the air pressure will be higher.

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DaniilM [7]
B. Knife HOpe this helps :3
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The ____ of an object is a measure of the amount of matter it contains. on the other hand ____ is a measure of the gravitational
Phoenix [80]
<span>The Gravitational Force of an object is a measure of the amount of matter it contains. on the other hand __Matter__ is a measure of the gravitational force on an object. I hope it helps :)</span>
7 0
3 years ago
When a 10 V battery is connected to a resistor, 5 A of current flows through the resistor. What is the resistor's value?
SashulF [63]

Given data

*The value of battery voltage is V = 10 V

*The current flows through the resistor is I = 5 A

The formula for the resistor is given by the Ohm's law as

R=\frac{V}{I}

Substitute the values in the above expression as

\begin{gathered} R=\frac{10}{5} \\ =2\text{ ohm} \end{gathered}

7 0
1 year ago
If 2.0×10^−4 C of charge passes a point in 2.0×10^−6 s , what is the rate of current flow?1.0×10^−10 A1.0×10^2 A4.0×10^−1 A4.0×1
Ipatiy [6.2K]

This problem is about the rate of the current. It's important to know that refers to the quotient between the electric charge and the time, that's the current rate.

I=\frac{Q}{t}

Where Q = 2.0×10^−4 C and t = 2.0×10^−6 s. Let's use these values to find I.

\begin{gathered} I=\frac{2.0\times10^{-4}C}{2.0\times10^{-6}\sec } \\ I=1.0\times10^{-4-(-6)}A \\ I=1.0\times10^{-4+6}A \\ I=1.0\times10^2A \end{gathered}

<em>As you can observe above, the division of the powers was solved by just subtracting their exponents.</em>

<em />

<h2>Therefore, the rate of the current flow is 1.0×10^2 A.</h2>
3 0
1 year ago
The magnetic field a distance 2 cm from a long straight current-carrying wire is 2 × 10–5 t. the current in the wire is:
Sliva [168]

Current in the wire = 2 A

Explanation:

the magnetic field is given by

B= \frac{\mu i}{2\pi r}

μo= 4π x 10⁻⁷ Tm/A

i= current

r=0.02 m

B = magnetic field= 2 x 10⁻⁵ T

2 x 10⁻⁵= (4π x 10⁻⁷)(i) / (2π*0.02)

i=2 A

6 0
3 years ago
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