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3 years ago

What is the frequency of this wave?

Physics

2 answers:

Musya8 [376]3 years ago

8 0

Answer:

its 2, not 4

Explanation:

brainlyest pleaseeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Reptile [31]3 years ago

3 0

It’s 4 because a coiled springs is closely spaced then widen

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Ten high-technology batteries are tested for 200 hours each. One failed at 20 hours; another failed at 140 hours; all others com

Bas_tet [7]

Answer:

Failure rate = 20%

MTBF = 880 hours

Explanation:

given data

batteries = 10

tested = 200 hours

one failed = 20 hours

another fail at = 140 hours

solution

we know that Mean Time between Failures is express as = (Total up time) ÷ (number of breakdowns) ....................1

so here Total up time will be

Total up time = 200 × 10

Total up time = 2000

and here

Number of breakdown = 1 at 20 hour and another at 140 hour = 2

so it will be = (Total up time) ÷ (number of breakdowns) .......2

= $\frac{2000}{2}$ = 1000

so here gap between occurrences is

gap between occurrences= 140 - 20

gap between occurrences = 120 hour

and

MTBF will be

MTBF = 1000 - 120

MTBF = 880 hours

and

Failure rate (FR) will be

Failure rate (FR) = 1 ÷ MTBF ................3

Failure rate (FR) = R÷T ......................4

as here R is the number of failures and T is total time

so Failure rate (FR) = 20%

4 0

3 years ago

Which statement is true about the atom?

slavikrds [6]

Answer:

Its d

atome contain

negative electrons,

positive protons and uncharged neutrons.

Explanation:

7 0

3 years ago

A wave changing shape when passing through an opening is an example of what?

igomit [66]

It is diffraction !!

7 0

3 years ago

Trivia Time!! At what velocity does light move?

Maslowich

Explanation:

Light Light from a moving source travels at 300,000 km/sec (186,000 miles/sec).

Note:

The Speed of Light Is Constant.

7 0

2 years ago

Read 2 more answers

Given Vout = 17.33 vpp and R1 = 3 kΩ, find the value of RF required to provide Av = 4.33. (Round your answer to 2 decimal places

Olenka [21]

Answer:

The magnitude of $V_{2}$ is 4 V and phase of input voltage is zero

Explanation:

Given:

Output voltage $V_{out} = 17.33$

Resistance $R_{1} = 3$ kΩ

Voltage gain $A_{v} = 4.33$

For finding feedback resistance we use gain equation

Gain equation for non inverting op-amp is given by,

$A_{v} = 1+\frac{R_{f} }{R_{1} }$

$4.33 = 1+ \frac{R_{f} }{3 k }$

$R_{f}$ ≅ 10 kΩ

For finding input voltage we use,

$A_{v} = \frac{V_{out} }{V_{2} }$

$V_{2} = \frac{17.33}{4.33}$

$V_{2} = 4$ V

The Phase of $V_{2}$ is zero because output voltage phase is 360°

Therefore, the magnitude of $V_{2}$ is 4 V and phase of input voltage is zero

7 0

3 years ago