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Zarrin [17]
3 years ago
5

The combined-gas law relates which of these?

Physics
1 answer:
Fofino [41]3 years ago
5 0
The combined-gas law relates which temperature, pressure and volume.

Temperature=T
Pressure=P
Volume=V

(P₁*V₁) / T₁=(P₂*V₂) / T₂

D. Temperature, pressuere and volume.
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How much power should a braked 1.5t car have to be braked to reduce its speed from 30m / s to 10m / s in 5s?​
grandymaker [24]

Answer:

-120000 W

Explanation:

Power = change in energy / time

P = ΔE / t

P = (½ mv₂² − ½ mv₁²) / t

P = m (v₂² − v₁²) / (2t)

Given m = 1.5 t = 1500 kg, v₂ = 10 m/s, v₁ = 30 m/s, and t = 5 s:

P = (1500 kg) ((10 m/s)² − (30 m/s)²) / (2 × 5 s)

P = -120000 W

7 0
3 years ago
A sonar pulse sent out by a boat arrives back after 4 seconds. If the speed of sound in water is 1600m/s, how deep is the water?
Varvara68 [4.7K]

Answer:

the boat would be deeped by 3200 m

Explanation:

Given that

The boat arrives back after 4 seconds

And, the speed of the sound in water is 1,600 m/s

We need to find out how much deep is the water

So,

As we know that

Distance = ( speed × time) ÷ 2

Here we divided by 2 because the boat arrives back

= (1600 × 4) ÷ 2

= 3200 m

Therefore the boat would be deeped by 3200 m

7 0
3 years ago
Your mother asks you to carry a load of wood to the fireplace and lower it to the hearth. In doing this you have used your arms
Evgesh-ka [11]

Answer: The correct answer is the weight of the wood.

Explanation:

Hope this helps

8 0
2 years ago
Read 2 more answers
An apple drops from the tree and falls freely. The apple is originally at rest a height H0 above the ground. The ground is cover
zzz [600]

Answer:

Explanation:

The distance travelled in the free fall is H - h  

Since the apple originally started from rest we can use v^2 =  u^2 + 2 x g x s  where v is the final velocity, g the accln due to gravity and s the distance travelled and u is the initial velocity = 0

So the velocity just before it enters the grass is sq rt [2 x g x (H - h)]

Once in the grass, it slows down at a constant rate which means that the acceleration (a) during this period is constant.

So once again using the same formula we have v = O and u = sq rt[2 x g x (H-h)]

so since v^2 = u^2 + 2 x a x s then  

O^2 = 2 x g x (H-h) + 2 x a x h

{O^2 - 2 x g x (H - h)}/(2 x h) = a

7 0
3 years ago
Numbered 8 nowwwwwww
amm1812

Torque =  r x F

|F| =  mg =  60 * 10 N = 600 N ( assuming g ~ 10m/s^2)

distance of fulcrum = torque / Force = 90/600 m = .15 m.

7 0
3 years ago
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