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Ket [755]
3 years ago
14

List 3 main types weathering​

Physics
2 answers:
swat323 years ago
5 0

Answer:

Weathering is the breakdown of rocks at the Earth's surface, by the action of rainwater, extremes of temperature, and biological activity. It does not involve the removal of rock material. There are three types of weathering, physical, chemical and biological.

Explanation:

Please give brainlest and points!

Bezzdna [24]3 years ago
5 0

Answer:

3 types of weathering are, physical, chemical and biological weathering.

Explanation:

Hope this helps and have a wonderful day!!!

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Enrique is given information about a satellite orbiting Earth. R = 3. 8 Ă— 108 m T = 18 days In order to calculate the tangentia
NISA [10]

The first step that  Enrique must take in order to calculate the tangential speed of the satellite is to convert the period from days to seconds.

We know that the SI unit of speed is meter per second and now, we with to obtain the tangential speed of the satellite.

Since the period is given in days, the first step is to convert the period from days to seconds.

Learn more: brainly.com/question/17638582

6 0
2 years ago
A sphere has surface area 1.25 m2, emissivity 1.0, and temperature 100.0°C. What is the rate at which it radiates heat into empt
Yuri [45]
The total power emitted by an object via radiation is:
P=A\epsilon \sigma T^4
where:
A is the surface of the object (in our problem, A=1.25 m^2
\epsilon is the emissivity of the object (in our problem, \epsilon=1)
\sigma = 5.67 \cdot 10^{-8} W/(m^2 K^4) is the Stefan-Boltzmann constant
T is the absolute temperature of the object, which in our case is T=100^{\circ} C=373 K

Substituting these values, we find the power emitted by radiation:
P=(1.25 m^2)(1.0)(5.67 \cdot 10^{-8}W/(m^2K^4)})(373 K)^4=1371 W = 1.4 kW
So, the correct answer is D.
6 0
3 years ago
A truck traveling at a constant speed of 28 m/s passes a more slowly moving car. The instant the truck passes the car, the car b
choli [55]

Answer:

the velocity of car when it passes the truck is u = 16.33 m/s

Explanation:

given,

constant speed of truck  = 28 m/s

acceleration of car = 1.2 m/s²

passes the truck in 545 m

speed of the car when it just pass the truck = ?

time taken by the truck to travel 545 m

              time =\dfrac{distance}{speed}

              time =\dfrac{545}{28}

              time =19.46 s

velocity of the car when it crosses the truck

S = ut + \dfrac{1}{2}at^2

545= u\times 19.46 + \dfrac{1}{2} \times 1.2 \times 19.46^2

u = 16.33 m/s

the velocity of car when it passes the truck is u = 16.33 m/s

5 0
3 years ago
Which of the following is/are true? Electromagnetic waves are created by accelerating charges. Electromagnetic waves are transve
Vikki [24]

Answer:

All of the above are true.

Explanation:

(a). true  

whenever  charge particle  move back and froth from its mean position then it will produce oscillating electric and magnetic fields, . so an em wave can be obtain by accelerating charge

(b). true

the electric field and the magnetic field have vibrations in the perpendicular direction along  the motion of the wave  so electromagnetic wave is a transverse wave. therefore, the EM wave is a Transverse wave

(c) true .

The Electromagnetic wave consists of the two mutually perpendicular electric and magnetic fields  and also both fields are  perpendicular to the direction of propagation of the wave.

(d) true .

An electromagnetic wave  carry  energy through  vacuum with a speed   of 3 \times 10^8 m/s  

   so , all of the above are true.

4 0
3 years ago
If two point masses 1kg & 4kg are seperated by a distance of 2m. Magnitude of gravitational force exerted by 1kg on 4kg is ?
Aliun [14]

Answer:

  • F = G Newtons

Explanation:

Given:

  • Mass of 1st body = 1\:kg
  • Mass of 2nd body = 4\:kg

To Find:

  • Magnitude of gravitational force

Solution:

Here, we have a formula

  • F=\dfrac{G.M_{1}.M_{2}}{r^{2}}

<u>Substituting the values</u>

\implies\:\:F = \dfrac{G(1)(4)}{2^{2}}

\implies\:\:F = \dfrac{4G}{4}

\implies\:\:F = \dfrac{\cancel{4}G}{\cancel{4}}

\implies\:\:\red{F = G}

Know More:

The applied formula for the above solution is

{\boxed{F_{G}=\dfrac{G.M_{1}.M_{2}}{r^{2}}}}

where,

  • F_{G} = Gravitational force
  • G = Gravitational constant
  • M_{1} = mass of 1st body
  • M_{2} = mass of 2nd body
  • r = distance between two bodies
6 0
3 years ago
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